There is a simple and inexpensive way.
Buy a full wave bridge, then add a string of diodes across the the + and minus legs. Now insert this inline (using the two "AC" terminals) on one side of your ac power supply. You will drop 1.4 volts plus .7 volts for every diode in your "string"...
So to drop 6 volts, you need 7 diodes (1.4 + 0.7 * 7)...plus the full wave bridge. Of course, be sure the diodes are rated for the current you need.
--- In firstname.lastname@example.org, "bernardcurnow" <bernard-curnow97@...> wrote:
> Dear All
> Can any one tell me how to reduce the 16v AC output to 10v AC to operate the point motors and uncouplers on the Z gauge Marklin units or would it be OK to use the 16c AC direct without damage to these units?. I am using DCC for the locos but all other operations will use the standard set up.
> Regards to all Bernard.