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Re: Regular expression bug?

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  • Mikolaj Machowski
    ... Trying with this: start=+ (class s* ) @
    Message 1 of 6 , Aug 1, 2003
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      On Fri, Aug 01, 2003 at 08:38:54PM +0200, Nikolai Weibull wrote:
      > * Nikolai Weibull <lone-star@...> [Jul, 31 2003 01:00]:
      > > OK, been trying to get this to work:
      > > syn region rubyString matchgroup=rubyStringDelimit
      > > \start=+\(class\s*\)\@<!<<-'\z(.*\)'.*\zs$+ end=+^\s*\z1$+ fold
      > >
      > > But this does not work. In fact, it seems one cannot have a
      > > word-character in front of \zs. Why is this so?
      > > ex.:
      > > syn match rubyString +<<-'EOL'\zs.*$+
      > > does not match
      > > INTERP._invoke("proc", "rb_out", "args", <<-'EOL')
      > > this, however, does
      > > syn match rubyString +<<-'\zs.*$+
      > > am i missing something vital here?
      > > nikolai
      > >
      > don't want to be a bitch, but does anyone know anything about this?
      > It's actually for a worthy cause. It would allow the Ruby construct
      > method(arg1, <<-EOF, arg2, ...)
      > text
      > EOF
      > to actually be highlighted correctly. Or if anyone could suggest a
      > better way of telling the match to begin on the next line, be my guest.
      > nikolai
      Trying with this:
      \start=+\(class\s*\)\@<!<<-'\z(.*\)'.*\zs$+ end=+^\s*\z1$+ fold

      \start=+\(class\s*\)\@<!<<-'\z([^']*\)'.*\zs$+ end=+^\s*\z1$+ fold

      But I am not sure if you can use \z(\) and \zs in one expression at
      all.

      m.
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    • Nikolai Weibull
      ... no, doesn t help...thanks for suggestion anyway. nikolai ... i can t see why they would be mutually exclusive, but yeah...maybe nikolai -- ...
      Message 2 of 6 , Aug 2, 2003
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        * Mikolaj Machowski <mikmach@...> [Aug, 02 2003 13:20]:
        > Trying with this:
        > \start=+\(class\s*\)\@<!<<-'\z(.*\)'.*\zs$+ end=+^\s*\z1$+ fold
        >
        > \start=+\(class\s*\)\@<!<<-'\z([^']*\)'.*\zs$+ end=+^\s*\z1$+ fold
        >
        no, doesn't help...thanks for suggestion anyway.
        nikolai

        > But I am not sure if you can use \z(\) and \zs in one expression at
        > all.
        i can't see why they would be mutually exclusive, but yeah...maybe
        nikolai

        --
        ::: name: Nikolai Weibull :: aliases: pcp / lone-star :::
        ::: born: Chicago, IL USA :: loc atm: Gothenburg, Sweden :::
        ::: page: www.pcppopper.org :: fun atm: gf,lps,ruby,php,war3 :::
        main(){printf(&linux["\021%six\012\0"],(linux)["have"]+"fun"-97);}
      • Benji Fisher
        ... Can you ask this as a regular-expression question (using a search, for example) rather than as a syntax question? That is, can you give a search pattern
        Message 3 of 6 , Aug 7, 2003
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          Nikolai Weibull wrote:
          > OK, been trying to get this to work:
          > syn region rubyString matchgroup=rubyStringDelimit
          > \start=+\(class\s*\)\@<!<<-'\z(.*\)'.*\zs$+ end=+^\s*\z1$+ fold
          >
          > But this does not work. In fact, it seems one cannot have a
          > word-character in front of \zs. Why is this so?
          > ex.:
          > syn match rubyString +<<-'EOL'\zs.*$+
          > does not match
          > INTERP._invoke("proc", "rb_out", "args", <<-'EOL')
          > this, however, does
          > syn match rubyString +<<-'\zs.*$+
          > am i missing something vital here?
          > nikolai

          Can you ask this as a regular-expression question (using a search,
          for example) rather than as a syntax question? That is, can you give a
          search pattern and a sample text that do not give the expected results?

          --Benji Fisher
        • Nikolai Weibull
          ... hm...no...the reason being that it works if you enter it as a search. nikolai -- ... main(){printf(&linux[ 021%six 012 0 ],(linux)[ have ]+ fun -97);}
          Message 4 of 6 , Aug 7, 2003
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            * Benji Fisher <benji@...> [Aug, 07 2003 17:50]:
            >
            > Can you ask this as a regular-expression question (using a search,
            > for example) rather than as a syntax question? That is, can you give a
            > search pattern and a sample text that do not give the expected results?
            >
            hm...no...the reason being that it works if you enter it as a search.
            nikolai

            --
            ::: name: Nikolai Weibull :: aliases: pcp / lone-star :::
            ::: born: Chicago, IL USA :: loc atm: Gothenburg, Sweden :::
            ::: page: www.pcppopper.org :: fun atm: gf,lps,ruby,php,war3 :::
            main(){printf(&linux["\021%six\012\0"],(linux)["have"]+"fun"-97);}
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