## Re: calculations on result from search

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• ... this ... subtract ... How does this work for you? %s/ ( d d ):00/ =substitute( 0 .(substitute(submatch(1), ^0* , , g )-1), .* (.. ) , 1 , ). :00
Message 1 of 4 , May 2, 2004
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> I have several files where I need to make some substitutions. In one of
this
> substitutions I need to make a calculation on a result from a search.
> For example, I have a column like this:
>
> 00:30
> 01:00
> 01:30
> 02:00
> ...
>
> I want to change only the lines that end with 00; on this lines I need to
subtract
> 1 from the number on left side of :. So, the result should be:

How does this work for you?

%s/\(\d\d\):00/\=substitute('0'.(substitute(submatch(1),
'^0*','','g')-1), '.*\(..\)', '\1', '').':00'

It's ugly, but it accomodates the wrinkle that vim considers leading zeros
an indicator of an octal number, which does funky stuff with the maths at
hand. So, it strips off the leading zero, decrements, tacks a leading zero
back onto it, and then pulls the two right-most characters. It doesn't
monkey with "00:00" any differently (you get a negative number--which may or
may not be the desired behavior)

Hope this helps,

-tim
• Thank you Roberto, Klaus, Mark and Trevor! All the solutions worked very well. Cheers, Marcelo
Message 2 of 4 , May 3, 2004
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Thank you Roberto, Klaus, Mark and Trevor!

All the solutions worked very well.

Cheers,

Marcelo

> On Sun, 2 May 2004, Luis Marcelo de Mattos Zeri wrote:
>
>> Hello,
>>
>> I have several files where I need to make some substitutions. In one
>> of this substitutions I need to make a calculation on a result from
>> a search. For example, I have a column like this:
>>
>> 00:30
>> 01:00
>> 01:30
>> 02:00
>> ...
>>
>> I want to change only the lines that end with 00; on this lines I need
>> to subtract 1 from the number on left side of :.
>
> :g/00\$/ exe "norm! 0\<C-X>"
>
> HTH
>
> Klaus
>
>
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