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Re: regexp: different match, re=1 vs re=0

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  • William Fugh
    ... Regards -William ... -- -- You received this message from the vim_use maillist. Do not top-post! Type your reply below the text you are replying to. For
    Message 1 of 4 , Aug 23, 2013
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      On Thu, Aug 22, 2013 at 10:14 PM, Bram Moolenaar <Bram@...> wrote:

      William Fugh wrote:

      > Version: 7.4, gVim, MS-DOS/MS-Windows
      > =========================================================
      > :%s#\[\(com\|ref\|ex\|p\|i\|u\|s\|b\)\]\zs\s\+\|\s\+\ze\[/\(com\|ref\|ex\|p\|i\|u\|s\|b\)\]\|[({]\zs\s\+\|\s\+\ze[)}]\|\s\zs\s\+\|\s\+\ze[,;.]\([^.,;]\)##g
      > ----------------------------------------------------------------------------------------------------------------
      > the command line as above, one line for test as follows, <Space> means a
      > space.
      > -----------------------------------------------------------------------------------------------------------------
      > This<Space>is<Space><Space><Space>[a<Space>test.
      > =========================================================
      > Result of re=1: This<Space>is<Space>[a<Space>test.
      > Result of re=0: This<Space>is<Space><Space>test.
      > ==============================================================*
      > Both of these regexp engines have the same result if the following command
      > line is used:-)*
      > ---------------------------------------------------------------------------------------------------------------------------
      > :%s#\[\(com\|ref\|ex\|p\|i\|u\|s\|b\)\]\zs\s\+\ze\|\zs\s\+\ze\[/\(com\|ref\|ex\|p\|i\|u\|s\|b\)\]\|[({]\zs\s\+\ze\|\zs\s\+\ze[)}]\|\s\zs\s\+\ze\|\zs\s\+\ze[,;.]\([^.,;]\)##g
      > ---------------------------------------------------------------------------------------------------------------------------

      That's a long regexp.  Can you reproduce it with a (much) shorter one?
       
      :%s#\s\+\ze\[/\|\s\zs\s\+##g          "result: (re=1) <> (re=0
      :%s#\s\+\ze\[/\|\s\zs\s\+\ze##g      "result: (re=1) == (re=0

      Regards
      -William


      On Thu, Aug 22, 2013 at 10:14 PM, Bram Moolenaar <Bram@...> wrote:

      William Fugh wrote:

      > Version: 7.4, gVim, MS-DOS/MS-Windows
      > =========================================================
      > :%s#\[\(com\|ref\|ex\|p\|i\|u\|s\|b\)\]\zs\s\+\|\s\+\ze\[/\(com\|ref\|ex\|p\|i\|u\|s\|b\)\]\|[({]\zs\s\+\|\s\+\ze[)}]\|\s\zs\s\+\|\s\+\ze[,;.]\([^.,;]\)##g
      > ----------------------------------------------------------------------------------------------------------------
      > the command line as above, one line for test as follows, <Space> means a
      > space.
      > -----------------------------------------------------------------------------------------------------------------
      > This<Space>is<Space><Space><Space>[a<Space>test.
      > =========================================================
      > Result of re=1: This<Space>is<Space>[a<Space>test.
      > Result of re=0: This<Space>is<Space><Space>test.
      > ==============================================================*
      > Both of these regexp engines have the same result if the following command
      > line is used:-)*
      > ---------------------------------------------------------------------------------------------------------------------------
      > :%s#\[\(com\|ref\|ex\|p\|i\|u\|s\|b\)\]\zs\s\+\ze\|\zs\s\+\ze\[/\(com\|ref\|ex\|p\|i\|u\|s\|b\)\]\|[({]\zs\s\+\ze\|\zs\s\+\ze[)}]\|\s\zs\s\+\ze\|\zs\s\+\ze[,;.]\([^.,;]\)##g
      > ---------------------------------------------------------------------------------------------------------------------------

      That's a long regexp.  Can you reproduce it with a (much) shorter one?

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