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Re: repeat with increment?

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  • Christian Brabandt
    Hi Hari! ... Not very. But I try to. But usually I do not think in those possible ways ;) ... Nice. regards, Christian
    Message 1 of 5 , Oct 1, 2009
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      Hi Hari!

      On Mi, 30 Sep 2009, Hari Krishna Dara wrote:

      > If you are comfortable with pythonic way of programming, you can get
      > the same with:

      Not very. But I try to. But usually I do not think in those possible
      ways ;)

      >
      > :echo join(map(range(3,64), 'v:val % 10'), '')
      > 34567890123456789012345678901234567890123456789012345678901234

      Nice.

      regards,
      Christian

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    • Bee
      ... Thank you, that is great, and the style I was looking for. vim is deep! -- Bill Santa Cruz, California
      Message 2 of 5 , Oct 1, 2009
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        On Oct 1, 2009, at 2:50 AM, Hari Krishna Dara wrote:
        > On Wed, Sep 30, 2009 at 10:31 PM, Christian Brabandt
        > <cblists@...> wrote:
        >> Hi Bee!
        >> On Mi, 30 Sep 2009, Bee wrote:
        >>> How to use something like repeat() to create a string like:
        >>>
        >>> '" '.(((start at 3 increment by 1) mod 10) for count of 62)
        >>>
        >>> resulting in:
        >>>
        >>> " 34567890123456789012345678901234567890123456789012345678901234
        >
        > ...
        >
        > If you are comfortable with pythonic way of programming, you can get
        > the same with:
        >
        > :echo join(map(range(3,64), 'v:val % 10'), '')
        > 34567890123456789012345678901234567890123456789012345678901234

        Thank you, that is great, and the style I was looking for.
        vim is deep!
        --
        Bill
        Santa Cruz, California


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