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137285Re: Substitution words within a partial match range help

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  • Ben Fritz
    Apr 18, 2013
      On Thursday, April 18, 2013 8:27:36 AM UTC-5, David Fishburn wrote:
      > Vim 7.3.758
      >
      >
      > I have the following string:
      >
      > 'match /\%(if\|elsif\|unless\|given\|when\|default\)\>/ match /\<\>/  nextgroup=perlElseIfError skip0 skip1 skip2'
      >
      >
      >
      > I was hoping (using 1 or 2 substitution commands) to find all words less than or equal to 5 characters in length and remove them.
      >
      >
      > But, these words have to be within "match /.../" tags.
      >
      >
      >
      > So, when completed, the string above should read:
      >
      > 'match /\%(\|\|unless\|\|\|default\)\>/ match /\<\>/  nextgroup=perlElseIfError skip0 skip1 skip2'
      >
      >
      >
      > Notice the skip0, skip1, skip2 are not touched since they are not within the beginning "match /" and the ending "/" of the match.
      >
      >
      > My best try was the following:
      >
      > >echo substitute( 'match /\%(if\|elsif\|unless\|given\|when\|default\)\>/ match /\<\>/  nextgroup=perlElseIfError skip0 skip1 skip2', '\<match /.\{-}\zs\<\w\{1,5}\>\ze.\{-}/ ', '', 'g' )
      >
      >
      >
      > But it only gets rid of the "if" at the start, and doesn't work on any of the other matches.
      >
      >
      > TIA,
      > David

      I got it working *better* using \@<= instead of \zs:

      \%(\<match /.\{-}\)\@<=\<\w\{1,5}\>\ze.\{-}/

      But this also removes the second "match" in the line, so you'll need to refine it some more, using [^/] instead of . to avoid that the ending '/' is allowed to match the beginning pattern:

      \%(\<match /[^/]\{-}\)\@<=\<\w\{1,5}\>\ze.\{-}/

      Now I think it works as you intended.

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