- Apologies if this is a big yawn to you all but I would like to know if ther is a quick way to determine ifr = 6*m*n + m + n where r, m, n are whole numbers.(One of the three dominant patterns in primes (6a + 1))
- It's symmetrical and can be seen as a bilinear function

f(m,n)=6*m*n+m+n

with a relation

r=f(m,n)

where for n,m>0

f(n+1,m)=f(m,n)+7

f(n,m)=f(m,n)

...

Thanks, it's a lot of value(s).

JD

--- In univalg@yahoogroups.com, William Ftabob <fatbobforman@...> wrote:

>

> Apologies if this is a big yawn to you all but I would like to know if ther is a quick way to determine if

> r = 6*m*n + m + n where r, m, n are whole numbers.

> (One of the three dominant patterns in primes (6a + 1))

> - --- In univalg@yahoogroups.com, "Jens" <jd@...> wrote:
>

> It's symmetrical and can be seen as a bilinear function

> f(m,n)=6*m*n+m+n

> with a relation

> r=f(m,n)

> where for n,m>0

> f(n+1,m)=f(m,n)+7

> f(n,m)=f(m,n)

> ...

> Thanks, it's a lot of value(s).

> JD

>

> --- In univalg@yahoogroups.com, William Ftabob <fatbobforman@> wrote:

> >

> > Apologies if this is a big yawn to you all but I would like to know if ther is a quick way to determine if

> > r = 6*m*n + m + n where r, m, n are whole numbers.

> > (One of the three dominant patterns in primes (6a + 1))

> >

>