## Re: Not to forget Pythagorean Considerations

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• Heres how that applies. If we take a full R value in series, the voltage across it will be the amperage times its ohmic value. This means that by reducing R by
Message 1 of 2 , Mar 30, 2012
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Heres how that applies. If we take a full R value in series, the voltage across it will be the amperage times its ohmic value. This means that by reducing R by one half, the voltage will also be halved. Now if the remaining half of the R value is given to X(L) as the R(int) value, the voltages across both X(L) and R/2 will not be summed or averaged. The new value corresponds to the hypotenus length using R/2 and X(L) as vector components. In other words we add the squares of both quantities, and then take the square root of the sum. If R<<L, then the new ohmic quantity will only be slightly larger. Thus adding internal resistance to L will increase the voltage across it in the LCR series.

--- In teslafy@yahoogroups.com, "Harvey D Norris" <harvich@...> wrote:
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