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Internal Capacity Squarings for 1-32 winds.

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  • Harvey D Norris
    01-00-31-00 30-00-00-03 00-02-00-32 00-29-04-00 ... also pairs with two past movements, and not merely one. ... starts on a horizontal basis of addition to
    Message 1 of 2 , Jan 5, 2009
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      > And the return starting with 29;
      > Previously 28 was paired with 5, so 29 must be paired with 4, but it
      > can only do this horizontally, instead of vertically, and now it
      also pairs with two past movements, and not merely one.
      > The vertical code of 33 is broken.
      > However on move 33, after the midpoint of windings; a new code
      starts on a horizontal basis of addition to seven square, or 49. Thus
      on seventh quadrant move 33 must land horizontally next to the former
      move of 16 formerly made in the fourth quadrant journey.
      Thus during the former last two quadrants of travel the journey has
      followed itself backwards from the path established by the first 16
      moves, but this method breaks down in the 7th quadrant; which is why I
      became confused. However the patterns are identical in that they
      consist of a clockwise chess knight pattern along the outside squares
      that circles the inside four squares, which is repeated above.
      Now if this were structured as a coil using insulated square
      windings where 64 volts appears across 64 winds, we can calculate the
      internal capacity on the basis of the voltage difference between
      windings. For a laterally wound coil of 64 square shaped windings in a
      64 array, the first layer of 8 has 7 differences of 1 volt between
      them. The electric energy stored between these square surface areas is
      1/2*C*V^2. The portion representing the capacity can be measured as
      the C value between just one adjacent surface area between two
      windings,and this is then repeatedly multiplied by the squarings of
      the voltage difference between windings. So here it can be seen that
      of these voltage differences between windings, there are seven sets of
      eight, or 56 on both a horizontal and vertical basis, for a total of
      110 internal capacities, of which for a laterally wound coil half of
      these consists of one volt differences in one dimension.
      On the other hand for the knight model the first time the winding
      is laid adjacent to another winding occurs on winding 17
      as the fourth quadrant placement shows, making for the first voltage
      measurement difference of 3^2. On the next wind 18, this is held in
      isolation from the rest of the return layer. However the next winding
      19 has both 3^2 and 5^2 voltage differences with former windings. And
      to finish for this quadrant another 5^2 difference is found between 15
      and 20.


      This gives 2(3^2 + 5^2) for the fourth quadrant.
      For the fifth quadrant of travel;

      Here we initially See that a voltage difference BETWEEN the quadrants
      exists between 9 and 20, or 11^2. 9^2 exists on the first movement of
      21, then 11^2, 13^2,15^2 summing to
      Quadrant 6;
      (17-23) squared
      Returning again to the seventh quadrant to finish the second layering;

      25-4=21, between quadrants, this seems to be duplicated as a voltage
      difference in the previous quadrant as 27-6=21
      For the first movement into the quadrant;
      and finally 31 is held in isolation for reference to future wind layers.
      this ends with 32-3= 31.

      I will later add these squarings to find the internal capacity for the
      first folded layer in this array.
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