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## Re: Errant Calculations

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• ... No ... . I used 32 1 ft by 1/2 inch aluminum square tubes for each side of a plate capacitor: with a 1/16th inch separation this read .73 nf for 12 by 16
Message 1 of 2 , May 1, 2007
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--- In teslafy@yahoogroups.com, "Harvey D Norris" <harvich@...> wrote:
>
> Mistakes in posted values noted. A new experiment begins. Middle
No
> 5 wind of the square array has itself been wound 72 or so times on
> each quadrature segment by paper coated steel windings, so those
> segments can be replaced for testing, but in the current bound
> arrangement everything must be dissasembled for new testings.
> HDN
. I used 32 1 ft by 1/2 inch aluminum
square tubes for each side of a plate capacitor: with
a 1/16th inch separation this read .73 nf for 12 by 16
inch plates. This took 64 aluminum square tubes in
total. However the same capacity could be obtained by
only using 4 X 9 = 36 tubes by building a coiled
capacity (9 winds in a square form)whereby using more
then just one side of the aluminum square conductors,
a higher capacity is gained per usage of the square
conductors. For the magic square winding case at
center wind disconnect, the dielectric barrier would
use double the amounts of windings expressing acting
internal capacity at center break then would a lateral
winding method. For the 9 magic square, 8 of the 12
internal capacities can be used for the calculation of
internal capacity, and both models show the same
capcity by meter of .73 nf. Now the inductance of
this coil model is ~ 57 uH @ 9 inch ave Radius; when
the center wind open capacitive state is given
conductivity. An arc gap can fluxuate between these L
and C values thus giving a resonant frequency, in this
case made by bringing an arc gap through the middle of
a coil construction designed to have maximum internal
capacity.
R(F) = 1/{6.28 sq rt [LC]}
=1/[6.28 * {2.04 *10^-7)]
= 780.5 khz
This figure is based on a mostly air gap between the
2D cap plates. Insertion of a full dielectric would
lower the frequency. Larger square arrays would be
predicted to do this also.
HDN
Steel windings are now in place for the center wind no 5
These now need connected by more steel around the corners
to form a complete (center) loop.(4 * 72 winds on the loop itself
at right angles to the loop itself; the windings are wrapped around
the middle aluminum segment.) LCR reading of 9 inch ave radius
is ~ 124 uH.( this is at 3 inch separation of inner corners, which
will be used as the standard for measurement comparisons.) Now we
shall see how the insertion of steel loops around the center winding
changes the inductance. Be back later when this is done.
HDN
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