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Re: [tancet] TANCET Math : Averages

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  • Munees M
    ________________________________ From: Ascent Education CAT, Classes, Groups To: tancet@yahoogroups.com Sent: Fri, February 19,
    Message 1 of 2 , Mar 1, 2010

      From: "Ascent Education CAT, Classes, Groups" <cat@...>
      To: tancet@yahoogroups.com
      Sent: Fri, February 19, 2010 1:58:38 PM
      Subject: [tancet] TANCET Math : Averages



      This question is from the topic Averages.

      5 years back the average age of A and B was 15 years. At present the average age of A, B and C is 20 years. How old is C?
      1. 20
      2. 15
      3. 30
      4. 40
      5. 45

      You could send your answer by replying to this mail or by posting your response at http://mbaforum. ascenteducation. com/tancet- math-averages- t1615.html

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      Ascent Education - TANCET MBA, MCA Classes @ Chennai
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      Ans for the question is no. 1 option i.e. 20

      The simplification is as follows:

      The avg age of A and B before 5 years is 15. i.e. (A+B)/2 = 15.

      Therefore, the present avrg age will be:


      Simplifying this eqn, weget

          =>       (A+B)= 40           ----(i)


      The present average age of A,B and C is 20 i.e (A+B+C)/3= 20

      Sub. eqn (i) in above eqn:  weget,

          =>       (40+C)=60

          =>       Thrfre, C= 60-40, i.e. 20years         

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