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Re: [tancet] TANCET Math : Averages

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  • Munees M
    ________________________________ From: Ascent Education CAT, Classes, Groups To: tancet@yahoogroups.com Sent: Fri, February 19,
    Message 1 of 2 , Mar 1, 2010
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      From: "Ascent Education CAT, Classes, Groups" <cat@...>
      To: tancet@yahoogroups.com
      Sent: Fri, February 19, 2010 1:58:38 PM
      Subject: [tancet] TANCET Math : Averages

       

      Hi

      This question is from the topic Averages.

      Question
      5 years back the average age of A and B was 15 years. At present the average age of A, B and C is 20 years. How old is C?
      1. 20
      2. 15
      3. 30
      4. 40
      5. 45

      You could send your answer by replying to this mail or by posting your response at http://mbaforum. ascenteducation. com/tancet- math-averages- t1615.html

      Best Wishes

      Ascent Education - TANCET MBA, MCA Classes @ Chennai
      Next Weekend batch @ Tambaram starts Feb 21, 2010
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      Ans for the question is no. 1 option i.e. 20

      The simplification is as follows:

      The avg age of A and B before 5 years is 15. i.e. (A+B)/2 = 15.

      Therefore, the present avrg age will be:

      (A+B)/2=(15+5)

      Simplifying this eqn, weget

          =>       (A+B)= 40           ----(i)

       

      The present average age of A,B and C is 20 i.e (A+B+C)/3= 20

      Sub. eqn (i) in above eqn:  weget,

          =>       (40+C)=60

          =>       Thrfre, C= 60-40, i.e. 20years         


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