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## Re: [tancet] TANCET Math : Averages

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• ________________________________ From: Ascent Education CAT, Classes, Groups To: tancet@yahoogroups.com Sent: Fri, February 19,
Message 1 of 2 , Mar 1, 2010

From: "Ascent Education CAT, Classes, Groups" <cat@...>
To: tancet@yahoogroups.com
Sent: Fri, February 19, 2010 1:58:38 PM
Subject: [tancet] TANCET Math : Averages

Hi

This question is from the topic Averages.

Question
5 years back the average age of A and B was 15 years. At present the average age of A, B and C is 20 years. How old is C?
1. 20
2. 15
3. 30
4. 40
5. 45

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Ans for the question is no. 1 option i.e. 20

The simplification is as follows:

The avg age of A and B before 5 years is 15. i.e. (A+B)/2 = 15.

Therefore, the present avrg age will be:

(A+B)/2=(15+5)

Simplifying this eqn, weget

=>       (A+B)= 40           ----(i)

The present average age of A,B and C is 20 i.e (A+B+C)/3= 20

Sub. eqn (i) in above eqn:  weget,

=>       (40+C)=60

=>       Thrfre, C= 60-40, i.e. 20years

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