By following the 9-cycle, you have the first 4 pairs in the same

layer. Consider it like the D layer ( made as a cross) .

The 4 next pairs are in the middle layer ( by analogy the F2L step).

And the last pair is in the U layer.

This alg leaves the last 3 pairs in U layer unsolved.

If you have 5-cycle by example, nevermind. Continue the preposition

with an other cycle.

Just you loose one pair. Most of the time, my alg leaves 4 pairs

unsolved. If I loose one pair (it's an unlucky case), you have 5

pairs unsolved.

But 4 or 5 pairs unsolved is the same (about).

I try to calculate the probabilities : having a cycle of minumum 9

pairs is possible most of the time, and it is not very important if

you loose one pair.

Have fun,

Frederick

--- In

speedsolvingrubikscube@yahoogroups.com, "Ron van Bruchem"

<ron@s...> wrote:

> Frédérick,

>

> Cool algorithm!

> But how do you easily set up this 9 cycle? And what if there is a

5 cycle

> instead of a 9 cycle?

>

> Have fun,

>

> Ron

>

> ----- Original Message -----

> From: "Frédérick BADIE" <f_badie@y...>

> To: <speedsolvingrubikscube@yahoogroups.com>

> Sent: Thursday, June 16, 2005 12:06 AM

> Subject: [Speed cubing group] 4*4*4 : 9 pairs of edge at once

>

>

> > Hi,

> >

> > I use this alg to solve 9 pairs of edge at once :

> >

> > L' F' U (Rr)' (Dd)' D' U' R U D R' (Dd) (Rr)

> >

> > 9 pairs is a max, 8 more often.

> > The first 3 moves don't touch the edge-pair, but it's an help to

> > preposition them.

> >

> > Frédérick.

> >