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Re: Ephemeris for SWAN sungrazer

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  • Rob
    Hi Rob - I was wondering if you could track the orbit back and give me very rough positions for 22 & 23 Feb 2012. I imaged bits of the Kreutz track at around
    Message 1 of 22 , Mar 10 6:25 AM
      Hi Rob - I was wondering if you could track the orbit back and give me very rough positions for 22 & 23 Feb 2012. I imaged bits of the Kreutz track at around 10:20 UT each evening. Fairly large fields covering several degrees of track. Didn't pick up anything in blinking but I did a pretty rushed job on it and the subs were noisy. I'd be interested to know if I was in the vicinity, understanding the uncertainties. Thanks.

      Cheers -

      Rob Kaufman
      Bright, Vic


      --- In sohohunter@yahoogroups.com, "Matson, Robert D." <matsonr@...> wrote:
      >
      > Hi All,
      >
      > Here is my predicted ephemeris for the next several days using e=1, i=142.
      > Keep in mind that the SWAN epochs are not known to better than +/- 12 hours,
      > so the precision here is far greater than the actual uncertainty. --Rob
      >
      >
      > Date (UT) .dd RA Dec delta r elong mag '/hr PA
      > ---- -- ----- -------- --------- ------ ------ ----- --- ------ -----
      > 2012 03 10.00 00 32 25 -06 54 27 1.0594 .32346 17.8 8.9 4.24 303.0
      > 2012 03 10.25 00 30 58 -06 40 36 1.0595 .31310 17.2 8.9 4.33 302.3
      > 2012 03 10.50 00 29 28 -06 26 40 1.0595 .30257 16.5 8.8 4.46 301.5
      > 2012 03 10.75 00 27 55 -06 12 37 1.0596 .29187 15.9 8.7 4.54 301.3
      >
      > 2012 03 11.00 00 26 21 -05 58 27 1.0597 .28099 15.3 8.6 4.60 301.0
      > 2012 03 11.25 00 24 44 -05 44 12 1.0597 .26992 14.7 8.5 4.73 300.3
      > 2012 03 11.50 00 23 04 -05 29 50 1.0597 .25864 14.0 8.4 4.89 299.5
      > 2012 03 11.75 00 21 20 -05 15 19 1.0596 .24713 13.3 8.3 5.00 299.1
      >
      > 2012 03 12.00 00 19 33 -05 00 39 1.0596 .23538 12.6 8.2 5.11 298.7
      > 2012 03 12.25 00 17 43 -04 45 52 1.0594 .22336 11.9 8.1 5.29 297.9
      > 2012 03 12.50 00 15 48 -04 30 56 1.0591 .21105 11.2 7.9 5.52 297.0
      > 2012 03 12.75 00 13 47 -04 15 48 1.0588 .19842 10.5 7.8 5.70 296.4
      >
      > 2012 03 13.00 00 11 42 -04 00 29 1.0584 .18543 9.7 7.6 5.90 295.8
      > 2012 03 13.25 00 09 31 -03 44 59 1.0578 .17204 8.9 7.4 6.20 294.8
      > 2012 03 13.50 00 07 12 -03 29 15 1.0570 .15820 8.1 7.2 6.56 293.8
      > 2012 03 13.75 00 04 43 -03 13 16 1.0560 .14384 7.3 6.9 6.91 292.9
      >
      > 2012 03 14.00 00 02 06 -02 57 02 1.0548 .12888 6.4 6.6 7.33 291.8
      > 2012 03 14.25 23 59 15 -02 40 32 1.0531 .11322 5.4 6.2 7.94 290.4
      > 2012 03 14.50 23 56 07 -02 23 47 1.0507 .09673 4.4 5.8 8.73 288.8
      > 2012 03 14.75 23 52 38 -02 06 51 1.0473 .07923 3.3 5.2 9.71 286.9
      >
      > 2012 03 15.00 23 48 39 -01 50 04 1.0422 .06059 2.1 4.3 11.10 284.3
      > 2012 03 15.25 23 43 58 -01 34 45 1.0330 .04106 0.8 3.0 13.02 279.7
      > 2012 03 15.50 23 38 43 -01 27 57 1.0130 .02512 1.0 2.5 11.40 265.8
      > 2012 03 15.75 23 36 54 -01 46 21 .97863 .03098 1.5 6.? 5.15 149.9
      >
      > 2012 03 16.00 23 39 07 -02 12 54 .95009 .04989 1.3 11.? 8.64 119.1
      >
    • sky@titan.physx.u-szeged.hu
      Hi All, What is on the right side on the latest (15:18:42 UT) Behind HI1 image? A head of the bright Kreutz sungrazer? :-) http://stereo.gsfc.nasa.gov/beacon/
      Message 2 of 22 , Mar 10 8:05 AM
        Hi All,

        What is on the right side on the latest (15:18:42 UT) Behind HI1 image? A head
        of the bright Kreutz sungrazer? :-)

        http://stereo.gsfc.nasa.gov/beacon/

        Regards,
        K.


        > Hi All,
        >
        > I haven't seen an image from 3/5 for SWAN, so I just used the 4th, 6th and
        > 7th. Here is my rough astrometry:
        >
        > SWAN012 S2012 03 04.50000 01 00 54.0 -11 32 00
        > 249
        > SWAN012 s2012 03 04.50000 1 +1109341.08 -895029.140 -377282.698
        > 249
        > SWAN012 S2012 03 06.50000 00 52 00.0 -10 09 00
        > 249
        > SWAN012 s2012 03 06.50000 1 +1133468.57 -847847.964 -348279.446
        > 249
        > SWAN012 S2012 03 07.50000 00 47 06.0 -08 55 00 9.0
        > 249
        > SWAN012 s2012 03 07.50000 1 +1145428.25 -823289.676 -333358.809
        > 249
        >
        > I forwarded this to Dan Green, let him know that the object was first
        > discovered by Vladimir, and provided an orbital solution assuming
        > e=1, i=144 (e.g. Kreutz family):
        >
        > Orbital elements:
        > SWAN012
        > Perihelion 2012 Mar 15.875006 TT; Constraint: i=144,e=1
        > Epoch 2012 Mar 6.0 TT = JDT 2455992.5 Earth MOID: 0.4761
        > M 359.99999 (2000.0) P Q
        > n 0.00000002 Peri. 72.97600 0.43775118 -0.89178638
        > a 117390.672 Node 11.22460 -0.86743398 -0.45237562
        > e 0.9999996 Incl. 143.99999 0.23649987 -0.00856424
        > P40220770 H 8.8 G 0.15 q 0.03603431 Q 234781.309
        > From 3 observations 2012 Mar. 4-7; mean residual 418".375.
        >
        > My astronaut friend, Don Pettit, has been notified and will attempt to
        > find it and photograph it from the International Space Station (assuming
        > it's bright enough). --Rob
        >
      • terryjlovejoy
        First of all, congratulations to Vladimir for his find! Having seen the SWAN images now, it is pretty clearly a real object. Unfortunately, my attempts to
        Message 3 of 22 , Mar 10 3:58 PM
          First of all, congratulations to Vladimir for his find!

          Having seen the SWAN images now, it is pretty clearly a real object.

          Unfortunately, my attempts to confirm the comet have failed which is likely a result of insufficient limiting magnitude and/or the fact I was not looking close enough to the sun. With my attempt last night (10.37 UT) I took a number of 3 second exposures using a 135mm f3.5 lens and camera DSLR. I was able to spot an 8th magnitude star 16 degrees elongation from the sun along the sungrazing path. In order to get a clear western view I had to setup my camera amongst a palm tree at the top of my property!

          Terry
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