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Re: Local oscillator problem

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  • tinusrammstein
    Hi Ulo, Okay i did not know that there was a standard way for marking these :) With my multimeter on diode test mode and only the 12 v plugged in, i meusure
    Message 1 of 17 , Sep 1, 2012
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      Hi Ulo,

      Okay i did not know that there was a standard way for marking these :)

      With my multimeter on diode test mode and only the 12 v plugged in, i meusure the following values.

      u4 (pin 1 and 2) - Infinte(Overload)
      u5 (pin 1 and 2) - 1.472

      I also re-meusured u4 and u5 with 12v and usb plugged in.

      u4 (pin1 and 2) - 6MHZ - 5Volt
      u4 (pin 1 and 2) - 10Mhz - 0.0V

      u5 (pin 1 and 2) 6MHZ - 0.0V
      u5 (pin 1 and 2) 10Mhz - 1.0 Volt

      The output of u4 is always 5 Volt...

      73,
      Martijn


      --- In softrock40@yahoogroups.com, "ylo58" <umets@...> wrote:
      >
      >
      >
      >
      > Hi Martijn,
      >
      > you don't need to define the pin numbers, there is a standard way - counterclockwise from the marked one. Then we end up with same numbers as in circuit diagrams.
      >
      > It seems that you forgot to move the ground lead in this second measurement on U4 and U5, but this does not matter much at the moment. For some reason the input side of U4 behaves like a 21 kOhm resistor, instead of a forward-biased diode that it should be.
      >
      > We need to find out where the extra resistance resides, inside U4 or outside.
      >
      > You could measure between pins 1 and 2 with the diode test mode of a multimeter, with USB disconnected from Softrock. It should show about 1 V with pin 1 positive.
      > If it shows OL (overload), then U4 is defective. U5 works properly, so you can compare with it.
      > If the test is fine, then there must be a problem with solder connections or tracks to these pins.
      >
      > Regards,
      >
      > Ulo
      >
      > --- In softrock40@yahoogroups.com, "tinusrammstein" <tinusrammstein@> wrote:
      > >
      > > Hi Ulo,
      > >
      > > The black round dot is in the left upper corner for both u4 and u5.
      > > --------------------
      > > pin 1 - left upper
      > > pin 2 - left under
      > > pin 3 - right upper
      > > pin 4 - right under
      > >
      > >
      > > u4 - pin 1 (02mhz) = 0 V
      > > u4 - pin 1 (06mhz) = 0 V
      > > u4 - pin 1 (12mhz) = 0 V
      > > u4 - pin 1 (24mhz) = 0 V
      > >
      > > u4 - pin 2 (02mhz) = 0 V
      > > u4 - pin 2 (06mhz) = 0 V
      > > u4 - pin 2 (12mhz) = 0 V
      > > u4 - pin 2 (24mhz) = 0 V
      > >
      > > u4 - pin 3 (02mhz) = 5 V
      > > u4 - pin 3 (06mhz) = 5 V
      > > u4 - pin 3 (12mhz) = 5 V
      > > u4 - pin 3 (24mhz) = 5 V
      > >
      > > u4 - pin 4 (02mhz) = 0 V
      > > u4 - pin 4 (06mhz) = 0 V
      > > u4 - pin 4 (12mhz) = 0 V
      > > u4 - pin 4 (24mhz) = 0 V
      > >
      > >
      > >
      > > u5 - pin 1 (02mhz) = 0 V
      > > u5 - pin 1 (06mhz) = 0 V
      > > u5 - pin 1 (12mhz) = 0 V
      > > u5 - pin 1 (24mhz) = 0 V
      > >
      > > u5 - pin 2 (02mhz) = 0 V
      > > u5 - pin 2 (06mhz) = 0 V
      > > u5 - pin 2 (12mhz) = 0 V
      > > u5 - pin 2 (24mhz) = 0 V
      > >
      > > u5 - pin 3 (02mhz) = 0.16
      > > u5 - pin 3 (06mhz) = 5.01
      > > u5 - pin 3 (12mhz) = 0.24
      > > u5 - pin 3 (24mhz) = 5.02
      > >
      > > u5 - pin 4 (02mhz) = 0 V
      > > u5 - pin 4 (06mhz) = 0 V
      > > u5 - pin 4 (12mhz) = 0 V
      > > u5 - pin 4 (24mhz) = 0 V
      > >
      >
    • cbayona.cb
      A diode test is a resistance test, you never run a resistance test with power unless you want to burn out your meter. ... Cecil - k5nwa
      Message 2 of 17 , Sep 1, 2012
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        A diode test is a resistance test, you never run a resistance test
        with power unless you want to burn out your meter.

        At 11:38 AM 9/1/2012, you wrote:
        >Hi Ulo,
        >
        >Okay i did not know that there was a standard way for marking these :)
        >
        >With my multimeter on diode test mode and only the 12 v plugged in,
        >i meusure the following values.
        >
        >u4 (pin 1 and 2) - Infinte(Overload)
        >u5 (pin 1 and 2) - 1.472
        >
        >I also re-meusured u4 and u5 with 12v and usb plugged in.
        >
        >u4 (pin1 and 2) - 6MHZ - 5Volt
        >u4 (pin 1 and 2) - 10Mhz - 0.0V
        >
        >u5 (pin 1 and 2) 6MHZ - 0.0V
        >u5 (pin 1 and 2) 10Mhz - 1.0 Volt
        >
        >The output of u4 is always 5 Volt...
        >
        >73,
        >Martijn
        >
        >
        >--- In softrock40@yahoogroups.com, "ylo58" <umets@...> wrote:
        > >
        > >
        > >
        > >
        > > Hi Martijn,
        > >
        > > you don't need to define the pin numbers, there is a standard way
        > - counterclockwise from the marked one. Then we end up with same
        > numbers as in circuit diagrams.
        > >
        > > It seems that you forgot to move the ground lead in this second
        > measurement on U4 and U5, but this does not matter much at the
        > moment. For some reason the input side of U4 behaves like a 21 kOhm
        > resistor, instead of a forward-biased diode that it should be.
        > >
        > > We need to find out where the extra resistance resides, inside U4
        > or outside.
        > >
        > > You could measure between pins 1 and 2 with the diode test mode
        > of a multimeter, with USB disconnected from Softrock. It should
        > show about 1 V with pin 1 positive.
        > > If it shows OL (overload), then U4 is defective. U5 works
        > properly, so you can compare with it.
        > > If the test is fine, then there must be a problem with solder
        > connections or tracks to these pins.
        > >
        > > Regards,
        > >
        > > Ulo
        > >
        > > --- In softrock40@yahoogroups.com, "tinusrammstein"
        > <tinusrammstein@> wrote:
        > > >
        > > > Hi Ulo,
        > > >
        > > > The black round dot is in the left upper corner for both u4 and u5.
        > > > --------------------
        > > > pin 1 - left upper
        > > > pin 2 - left under
        > > > pin 3 - right upper
        > > > pin 4 - right under
        > > >
        > > >
        > > > u4 - pin 1 (02mhz) = 0 V
        > > > u4 - pin 1 (06mhz) = 0 V
        > > > u4 - pin 1 (12mhz) = 0 V
        > > > u4 - pin 1 (24mhz) = 0 V
        > > >
        > > > u4 - pin 2 (02mhz) = 0 V
        > > > u4 - pin 2 (06mhz) = 0 V
        > > > u4 - pin 2 (12mhz) = 0 V
        > > > u4 - pin 2 (24mhz) = 0 V
        > > >
        > > > u4 - pin 3 (02mhz) = 5 V
        > > > u4 - pin 3 (06mhz) = 5 V
        > > > u4 - pin 3 (12mhz) = 5 V
        > > > u4 - pin 3 (24mhz) = 5 V
        > > >
        > > > u4 - pin 4 (02mhz) = 0 V
        > > > u4 - pin 4 (06mhz) = 0 V
        > > > u4 - pin 4 (12mhz) = 0 V
        > > > u4 - pin 4 (24mhz) = 0 V
        > > >
        > > >
        > > >
        > > > u5 - pin 1 (02mhz) = 0 V
        > > > u5 - pin 1 (06mhz) = 0 V
        > > > u5 - pin 1 (12mhz) = 0 V
        > > > u5 - pin 1 (24mhz) = 0 V
        > > >
        > > > u5 - pin 2 (02mhz) = 0 V
        > > > u5 - pin 2 (06mhz) = 0 V
        > > > u5 - pin 2 (12mhz) = 0 V
        > > > u5 - pin 2 (24mhz) = 0 V
        > > >
        > > > u5 - pin 3 (02mhz) = 0.16
        > > > u5 - pin 3 (06mhz) = 5.01
        > > > u5 - pin 3 (12mhz) = 0.24
        > > > u5 - pin 3 (24mhz) = 5.02
        > > >
        > > > u5 - pin 4 (02mhz) = 0 V
        > > > u5 - pin 4 (06mhz) = 0 V
        > > > u5 - pin 4 (12mhz) = 0 V
        > > > u5 - pin 4 (24mhz) = 0 V
        > > >
        > >
        >

        Cecil - k5nwa
        < http://thepartsplace.k5nwa.com/ > < http://www.softrockradio.org/ >

        Never take life seriously. Nobody gets out alive anyway.
      • ylo58
        Hi Martijn, it seems clear to me now that U4 must be replaced. Just in case, I would also double check the value of R5, to make sure that the new U4 does not
        Message 3 of 17 , Sep 1, 2012
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          Hi Martijn,

          it seems clear to me now that U4 must be replaced.
          Just in case, I would also double check the value of R5, to make sure that the new U4 does not get too much current.

          Regards,

          Ulo

          --- In softrock40@yahoogroups.com, "tinusrammstein" <tinusrammstein@...> wrote:
          >
          > Hi Ulo,
          >
          > Okay i did not know that there was a standard way for marking these :)
          >
          > With my multimeter on diode test mode and only the 12 v plugged in, i meusure the following values.
          >
          > u4 (pin 1 and 2) - Infinte(Overload)
          > u5 (pin 1 and 2) - 1.472
          >
          > I also re-meusured u4 and u5 with 12v and usb plugged in.
          >
          > u4 (pin1 and 2) - 6MHZ - 5Volt
          > u4 (pin 1 and 2) - 10Mhz - 0.0V
          >
          > u5 (pin 1 and 2) 6MHZ - 0.0V
          > u5 (pin 1 and 2) 10Mhz - 1.0 Volt
          >
          > The output of u4 is always 5 Volt...
          >
          > 73,
          > Martijn
          >
          >
          > --- In softrock40@yahoogroups.com, "ylo58" <umets@> wrote:
          > >
          > >
          > >
          > >
          > > Hi Martijn,
          > >
          > > you don't need to define the pin numbers, there is a standard way - counterclockwise from the marked one. Then we end up with same numbers as in circuit diagrams.
          > >
          > > It seems that you forgot to move the ground lead in this second measurement on U4 and U5, but this does not matter much at the moment. For some reason the input side of U4 behaves like a 21 kOhm resistor, instead of a forward-biased diode that it should be.
          > >
          > > We need to find out where the extra resistance resides, inside U4 or outside.
          > >
          > > You could measure between pins 1 and 2 with the diode test mode of a multimeter, with USB disconnected from Softrock. It should show about 1 V with pin 1 positive.
          > > If it shows OL (overload), then U4 is defective. U5 works properly, so you can compare with it.
          > > If the test is fine, then there must be a problem with solder connections or tracks to these pins.
          > >
          > > Regards,
          > >
          > > Ulo
          > >
          > > --- In softrock40@yahoogroups.com, "tinusrammstein" <tinusrammstein@> wrote:
          > > >
          > > > Hi Ulo,
          > > >
          > > > The black round dot is in the left upper corner for both u4 and u5.
          > > > --------------------
          > > > pin 1 - left upper
          > > > pin 2 - left under
          > > > pin 3 - right upper
          > > > pin 4 - right under
          > > >
          > > >
          > > > u4 - pin 1 (02mhz) = 0 V
          > > > u4 - pin 1 (06mhz) = 0 V
          > > > u4 - pin 1 (12mhz) = 0 V
          > > > u4 - pin 1 (24mhz) = 0 V
          > > >
          > > > u4 - pin 2 (02mhz) = 0 V
          > > > u4 - pin 2 (06mhz) = 0 V
          > > > u4 - pin 2 (12mhz) = 0 V
          > > > u4 - pin 2 (24mhz) = 0 V
          > > >
          > > > u4 - pin 3 (02mhz) = 5 V
          > > > u4 - pin 3 (06mhz) = 5 V
          > > > u4 - pin 3 (12mhz) = 5 V
          > > > u4 - pin 3 (24mhz) = 5 V
          > > >
          > > > u4 - pin 4 (02mhz) = 0 V
          > > > u4 - pin 4 (06mhz) = 0 V
          > > > u4 - pin 4 (12mhz) = 0 V
          > > > u4 - pin 4 (24mhz) = 0 V
          > > >
          > > >
          > > >
          > > > u5 - pin 1 (02mhz) = 0 V
          > > > u5 - pin 1 (06mhz) = 0 V
          > > > u5 - pin 1 (12mhz) = 0 V
          > > > u5 - pin 1 (24mhz) = 0 V
          > > >
          > > > u5 - pin 2 (02mhz) = 0 V
          > > > u5 - pin 2 (06mhz) = 0 V
          > > > u5 - pin 2 (12mhz) = 0 V
          > > > u5 - pin 2 (24mhz) = 0 V
          > > >
          > > > u5 - pin 3 (02mhz) = 0.16
          > > > u5 - pin 3 (06mhz) = 5.01
          > > > u5 - pin 3 (12mhz) = 0.24
          > > > u5 - pin 3 (24mhz) = 5.02
          > > >
          > > > u5 - pin 4 (02mhz) = 0 V
          > > > u5 - pin 4 (06mhz) = 0 V
          > > > u5 - pin 4 (12mhz) = 0 V
          > > > u5 - pin 4 (24mhz) = 0 V
          > > >
          > >
          >
        • tinusrammstein
          Hi Ulo, I ordered a new u4 - LTV 817 optocoupler.. This is what is meusure on R5 and R6 ... R5 - 1-7mhz - 0.37V R5 - 8-24mhz - 4.74V R6 - 1-7mhz - 4.89V R6 -
          Message 4 of 17 , Sep 2, 2012
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            Hi Ulo,

            I ordered a new u4 - LTV 817 optocoupler.. This is what is meusure on R5 and R6
            -------------------
            R5 - 1-7mhz - 0.37V
            R5 - 8-24mhz - 4.74V

            R6 - 1-7mhz - 4.89V
            R6 - 8-24mhz - 3.80V

            73,
            Martijn




            --- In softrock40@yahoogroups.com, "ylo58" <umets@...> wrote:
            >
            >
            >
            >
            > Hi Martijn,
            >
            > it seems clear to me now that U4 must be replaced.
            > Just in case, I would also double check the value of R5, to make sure that the new U4 does not get too much current.
            >
            > Regards,
            >
            > Ulo
            >
            > --- In softrock40@yahoogroups.com, "tinusrammstein" <tinusrammstein@> wrote:
            > >
            > > Hi Ulo,
            > >
            > > Okay i did not know that there was a standard way for marking these :)
            > >
            > > With my multimeter on diode test mode and only the 12 v plugged in, i meusure the following values.
            > >
            > > u4 (pin 1 and 2) - Infinte(Overload)
            > > u5 (pin 1 and 2) - 1.472
            > >
            > > I also re-meusured u4 and u5 with 12v and usb plugged in.
            > >
            > > u4 (pin1 and 2) - 6MHZ - 5Volt
            > > u4 (pin 1 and 2) - 10Mhz - 0.0V
            > >
            > > u5 (pin 1 and 2) 6MHZ - 0.0V
            > > u5 (pin 1 and 2) 10Mhz - 1.0 Volt
            > >
            > > The output of u4 is always 5 Volt...
            > >
            > > 73,
            > > Martijn
            > >
            > >
            > > --- In softrock40@yahoogroups.com, "ylo58" <umets@> wrote:
            > > >
            > > >
            > > >
            > > >
            > > > Hi Martijn,
            > > >
            > > > you don't need to define the pin numbers, there is a standard way - counterclockwise from the marked one. Then we end up with same numbers as in circuit diagrams.
            > > >
            > > > It seems that you forgot to move the ground lead in this second measurement on U4 and U5, but this does not matter much at the moment. For some reason the input side of U4 behaves like a 21 kOhm resistor, instead of a forward-biased diode that it should be.
            > > >
            > > > We need to find out where the extra resistance resides, inside U4 or outside.
            > > >
            > > > You could measure between pins 1 and 2 with the diode test mode of a multimeter, with USB disconnected from Softrock. It should show about 1 V with pin 1 positive.
            > > > If it shows OL (overload), then U4 is defective. U5 works properly, so you can compare with it.
            > > > If the test is fine, then there must be a problem with solder connections or tracks to these pins.
            > > >
            > > > Regards,
            > > >
            > > > Ulo
            > > >
            > > > --- In softrock40@yahoogroups.com, "tinusrammstein" <tinusrammstein@> wrote:
            > > > >
            > > > > Hi Ulo,
            > > > >
            > > > > The black round dot is in the left upper corner for both u4 and u5.
            > > > > --------------------
            > > > > pin 1 - left upper
            > > > > pin 2 - left under
            > > > > pin 3 - right upper
            > > > > pin 4 - right under
            > > > >
            > > > >
            > > > > u4 - pin 1 (02mhz) = 0 V
            > > > > u4 - pin 1 (06mhz) = 0 V
            > > > > u4 - pin 1 (12mhz) = 0 V
            > > > > u4 - pin 1 (24mhz) = 0 V
            > > > >
            > > > > u4 - pin 2 (02mhz) = 0 V
            > > > > u4 - pin 2 (06mhz) = 0 V
            > > > > u4 - pin 2 (12mhz) = 0 V
            > > > > u4 - pin 2 (24mhz) = 0 V
            > > > >
            > > > > u4 - pin 3 (02mhz) = 5 V
            > > > > u4 - pin 3 (06mhz) = 5 V
            > > > > u4 - pin 3 (12mhz) = 5 V
            > > > > u4 - pin 3 (24mhz) = 5 V
            > > > >
            > > > > u4 - pin 4 (02mhz) = 0 V
            > > > > u4 - pin 4 (06mhz) = 0 V
            > > > > u4 - pin 4 (12mhz) = 0 V
            > > > > u4 - pin 4 (24mhz) = 0 V
            > > > >
            > > > >
            > > > >
            > > > > u5 - pin 1 (02mhz) = 0 V
            > > > > u5 - pin 1 (06mhz) = 0 V
            > > > > u5 - pin 1 (12mhz) = 0 V
            > > > > u5 - pin 1 (24mhz) = 0 V
            > > > >
            > > > > u5 - pin 2 (02mhz) = 0 V
            > > > > u5 - pin 2 (06mhz) = 0 V
            > > > > u5 - pin 2 (12mhz) = 0 V
            > > > > u5 - pin 2 (24mhz) = 0 V
            > > > >
            > > > > u5 - pin 3 (02mhz) = 0.16
            > > > > u5 - pin 3 (06mhz) = 5.01
            > > > > u5 - pin 3 (12mhz) = 0.24
            > > > > u5 - pin 3 (24mhz) = 5.02
            > > > >
            > > > > u5 - pin 4 (02mhz) = 0 V
            > > > > u5 - pin 4 (06mhz) = 0 V
            > > > > u5 - pin 4 (12mhz) = 0 V
            > > > > u5 - pin 4 (24mhz) = 0 V
            > > > >
            > > >
            > >
            >
          • ylo58
            OK. I had in mind making sure that R5 actually is about 2.2 kOhm and not drastically less, for example 22 Ohm. This can be done with an ohmmeter in unpowered
            Message 5 of 17 , Sep 2, 2012
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              OK. I had in mind making sure that R5 actually is about 2.2 kOhm and not drastically less, for example 22 Ohm. This can be done with an ohmmeter in unpowered circuit.

              Regards,
              Ulo

              --- In softrock40@yahoogroups.com, "tinusrammstein" <tinusrammstein@...> wrote:
              >
              > Hi Ulo,
              >
              > I ordered a new u4 - LTV 817 optocoupler.. This is what is meusure on R5 and R6
              > -------------------
              > R5 - 1-7mhz - 0.37V
              > R5 - 8-24mhz - 4.74V
              >
              > R6 - 1-7mhz - 4.89V
              > R6 - 8-24mhz - 3.80V
              >
              > 73,
              > Martijn
            • tinusrammstein
              Hi, Ulo I unpowered the softrock and meusured the following values.. R5 = 2.16K Ohm R6 = 2.16K Ohm R12 = 10.53K Ohm R13 = 10.53K Ohm 73, Martijn
              Message 6 of 17 , Sep 2, 2012
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                Hi, Ulo

                I unpowered the softrock and meusured the following values..

                R5 = 2.16K Ohm
                R6 = 2.16K Ohm
                R12 = 10.53K Ohm
                R13 = 10.53K Ohm

                73,
                Martijn


                --- In softrock40@yahoogroups.com, "ylo58" <umets@...> wrote:
                >
                >
                >
                > OK. I had in mind making sure that R5 actually is about 2.2 kOhm and not drastically less, for example 22 Ohm. This can be done with an ohmmeter in unpowered circuit.
                >
                > Regards,
                > Ulo
                >
                > --- In softrock40@yahoogroups.com, "tinusrammstein" <tinusrammstein@> wrote:
                > >
                > > Hi Ulo,
                > >
                > > I ordered a new u4 - LTV 817 optocoupler.. This is what is meusure on R5 and R6
                > > -------------------
                > > R5 - 1-7mhz - 0.37V
                > > R5 - 8-24mhz - 4.74V
                > >
                > > R6 - 1-7mhz - 4.89V
                > > R6 - 8-24mhz - 3.80V
                > >
                > > 73,
                > > Martijn
                >
              • ylo58
                Hi Martijn, this confirms that R5 is fine and can not have caused the failure. When removing the defective optocoupler, you can cut off the pins and remove the
                Message 7 of 17 , Sep 2, 2012
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                  Hi Martijn,

                  this confirms that R5 is fine and can not have caused the failure.
                  When removing the defective optocoupler, you can cut off the pins and remove the body first, and then unsolder the pins one by one.
                  The holes can be cleared using solder wick.

                  Regards,

                  Ulo

                  --- In softrock40@yahoogroups.com, "tinusrammstein" <tinusrammstein@...> wrote:
                  >
                  > Hi, Ulo
                  >
                  > I unpowered the softrock and meusured the following values..
                  >
                  > R5 = 2.16K Ohm
                  > R6 = 2.16K Ohm
                  > R12 = 10.53K Ohm
                  > R13 = 10.53K Ohm
                  >
                  > 73,
                  > Martijn
                  >
                  >
                  > --- In softrock40@yahoogroups.com, "ylo58" <umets@> wrote:
                  > >
                  > >
                  > >
                  > > OK. I had in mind making sure that R5 actually is about 2.2 kOhm and not drastically less, for example 22 Ohm. This can be done with an ohmmeter in unpowered circuit.
                  > >
                  > > Regards,
                  > > Ulo
                  > >
                  > > --- In softrock40@yahoogroups.com, "tinusrammstein" <tinusrammstein@> wrote:
                  > > >
                  > > > Hi Ulo,
                  > > >
                  > > > I ordered a new u4 - LTV 817 optocoupler.. This is what is meusure on R5 and R6
                  > > > -------------------
                  > > > R5 - 1-7mhz - 0.37V
                  > > > R5 - 8-24mhz - 4.74V
                  > > >
                  > > > R6 - 1-7mhz - 4.89V
                  > > > R6 - 8-24mhz - 3.80V
                  > > >
                  > > > 73,
                  > > > Martijn
                  > >
                  >
                • tinusrammstein
                  Hi Ulo and other RX builders, Yesterday i finally received my new optocoupler. And U4 was indeed defective :) now the readings on R12 and R13 are correct! But
                  Message 8 of 17 , Sep 9, 2012
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                    Hi Ulo and other RX builders,

                    Yesterday i finally received my new optocoupler.

                    And U4 was indeed defective :) now the readings on R12 and R13 are correct! But my softrock is still not working ;(

                    These steps are working:
                    1. Power supply
                    2. USB power supply
                    3. Local oscillator and control
                    5. Auto Band pass filter
                    7. Operational Amplifier

                    Voltage problems with these steps:
                    4. Quadrature Clock generator
                    6. Quadrature Sampling detector

                    On stage 4 I meusure the following voltages on the u6 - 74ac74:
                    pin 1: 5.07 V
                    pin 2: 2.2 V
                    pin 3: 2.5 V
                    pin 4: 5.04 V
                    pin 5: 2.2 V
                    pin 6: 2.2 V
                    pin 7: 0 gnd
                    pin 8: 2.22 V
                    pin 9: 2.21 V
                    pin 10: 5.04 V
                    pin 11: 2.51 V
                    pin 12: 2.2 V
                    pin 13: 5.03 V
                    pin 14: 5.05 V

                    The voltages on 2,6,5,8,9,12 is 2.2 volt is this correct?

                    On stage 6 I meusure the following voltages on u10 - FST3253
                    pin 1: 0(GND)
                    pin 2: 2.09 V
                    pin 3: 2.51 V
                    pin 4: 0.45 V
                    pin 5: 2.51 V
                    pin 6: 2.51 V
                    pin 7: 2.51 V
                    pin 8: 0(GND)
                    pin 9: 2.51 V
                    pin 10: 2.34 V
                    pin 11: 2.51 V
                    pin 12: 2.51 V
                    pin 13: 0.51 V
                    pin 14: 2.07 V
                    pin 15: 0(GND)
                    pin 16: 5.06 V

                    The voltage on pin 2 comes from stage 4 the 74ac74.
                    Dont know why the voltages on pin 4 and 13 is so low?

                    I hope somebody can help me :)

                    Kind regards,
                    Martijn






                    --- In softrock40@yahoogroups.com, "ylo58" <umets@...> wrote:
                    >
                    >
                    >
                    >
                    > Hi Martijn,
                    >
                    > this confirms that R5 is fine and can not have caused the failure.
                    > When removing the defective optocoupler, you can cut off the pins and remove the body first, and then unsolder the pins one by one.
                    > The holes can be cleared using solder wick.
                    >
                    > Regards,
                    >
                    > Ulo
                    >
                    > --- In softrock40@yahoogroups.com, "tinusrammstein" <tinusrammstein@> wrote:
                    > >
                    > > Hi, Ulo
                    > >
                    > > I unpowered the softrock and meusured the following values..
                    > >
                    > > R5 = 2.16K Ohm
                    > > R6 = 2.16K Ohm
                    > > R12 = 10.53K Ohm
                    > > R13 = 10.53K Ohm
                    > >
                    > > 73,
                    > > Martijn
                    > >
                    > >
                    > > --- In softrock40@yahoogroups.com, "ylo58" <umets@> wrote:
                    > > >
                    > > >
                    > > >
                    > > > OK. I had in mind making sure that R5 actually is about 2.2 kOhm and not drastically less, for example 22 Ohm. This can be done with an ohmmeter in unpowered circuit.
                    > > >
                    > > > Regards,
                    > > > Ulo
                    > > >
                    > > > --- In softrock40@yahoogroups.com, "tinusrammstein" <tinusrammstein@> wrote:
                    > > > >
                    > > > > Hi Ulo,
                    > > > >
                    > > > > I ordered a new u4 - LTV 817 optocoupler.. This is what is meusure on R5 and R6
                    > > > > -------------------
                    > > > > R5 - 1-7mhz - 0.37V
                    > > > > R5 - 8-24mhz - 4.74V
                    > > > >
                    > > > > R6 - 1-7mhz - 4.89V
                    > > > > R6 - 8-24mhz - 3.80V
                    > > > >
                    > > > > 73,
                    > > > > Martijn
                    > > >
                    > >
                    >
                  • Alan
                    ... Subject: [softrock40] Re: Local oscillator problem ... Martijn Yes, you are measuring with RF square waves on these pins. As Robby says, worry when they
                    Message 9 of 17 , Sep 10, 2012
                    • 0 Attachment
                      ----- Original Message -----
                      Subject: [softrock40] Re: Local oscillator problem


                      > 6. Quadrature Sampling detector
                      >
                      > On stage 4 I meusure the following voltages on the u6 - 74ac74:
                      >
                      > The voltages on 2,6,5,8,9,12 is 2.2 volt is this correct?

                      Martijn

                      Yes, you are measuring with RF square waves on these pins. As Robby says, worry when they are 0 or 5 volts.

                      >
                      > On stage 6 I meusure the following voltages on u10 - FST3253
                      > Dont know why the voltages on pin 4 and 13 is so low?

                      This is strange.
                      They are not used but would normally be about 2V5.
                      If they were shorted to ground then I'd expect them to affect other pins.
                      Maybe the FST3253 is faulty. But the pins that are used are correct.

                      If no-one else has an answer I suggest you remember this and carry on to the next stage, you are almost there, maybe it will work.

                      73 Alan G4ZFQ
                    • ylo58
                      ... Very strange indeed. Losing more than 0.1 V on connections from U6 to U10 might be due to RF square wave effect. But pins 4, 5, 10, and 13 should be
                      Message 10 of 17 , Sep 10, 2012
                      • 0 Attachment
                        --- In softrock40@yahoogroups.com, "Alan" <alan4alan@...> wrote:
                        >
                        >
                        > ----- Original Message -----
                        > Subject: [softrock40] Re: Local oscillator problem
                        >
                        >
                        > > 6. Quadrature Sampling detector
                        > >
                        > > On stage 4 I meusure the following voltages on the u6 - 74ac74:
                        > >
                        > > The voltages on 2,6,5,8,9,12 is 2.2 volt is this correct?
                        >
                        > Martijn
                        >
                        > Yes, you are measuring with RF square waves on these pins. As Robby says, worry when they are 0 or 5 volts.
                        >
                        > >
                        > > On stage 6 I meusure the following voltages on u10 - FST3253
                        > > Dont know why the voltages on pin 4 and 13 is so low?
                        >
                        > This is strange.
                        > They are not used but would normally be about 2V5.
                        > If they were shorted to ground then I'd expect them to affect other pins.
                        > Maybe the FST3253 is faulty. But the pins that are used are correct.
                        >
                        > If no-one else has an answer I suggest you remember this and carry on to the next stage, you are almost there, maybe it will work.
                        >
                        > 73 Alan G4ZFQ
                        >

                        Very strange indeed.
                        Losing more than 0.1 V on connections from U6 to U10 might be due to RF square wave effect.
                        But pins 4, 5, 10, and 13 should be similar, they all are connected to the outputs for 1/4 of the RF period. One could speculate that since the pins with low voltage (4 and 13) both require S1 (pin 2) high, there could be something wrong with this switching signal.
                        Maybe try resoldering pin 2 of U10?
                        The only multimeter test that I can think of, would be the check of all pins of U10 for resistance to ground. In an unpowered circuit of course. This should reveal the possible partial shorts between tracks.

                        If this reveals nothing, then follow Alan's advice.

                        Regards,
                        Ulo
                      • tinusrammstein
                        Hello Alan and Ulo Finally my softrock is working, thank you SO much! :) it was indeed pin number 2, i resoldered the pin and now it s working! Now my next
                        Message 11 of 17 , Sep 30, 2012
                        • 0 Attachment
                          Hello Alan and Ulo

                          Finally my softrock is working, thank you SO much! :) it was indeed pin number 2, i resoldered the pin and now it's working!

                          Now my next question is this on the 7mhz(40M) band my receiption is superb if i compare the stations, i hear with my yeasu frg-7700... But when i tune my sofrock to the 10Mhz band and up the reception is horrible..

                          Iam using a g5rv long wire anntenna.

                          I made some printscreen's maybee you or someone else can help me...

                          http://tinus12342.nl/7mhz.png 
                          http://tinus12342.nl/10mhz.png 
                          http://tinus12342.nl/14mhz.png 

                          (i know it's in stereo mode, but then you can see the problem much better)


                          Kind Regards



                          --- In softrock40@yahoogroups.com, "ylo58" <umets@...> wrote:
                          >
                          >
                          >
                          >
                          >
                          > --- In softrock40@yahoogroups.com, "Alan" <alan4alan@> wrote:
                          > >
                          > >
                          > > ----- Original Message -----
                          > > Subject: [softrock40] Re: Local oscillator problem
                          > >
                          > >
                          > > > 6. Quadrature Sampling detector
                          > > >
                          > > > On stage 4 I meusure the following voltages on the u6 - 74ac74:
                          > > >
                          > > > The voltages on 2,6,5,8,9,12 is 2.2 volt is this correct?
                          > >
                          > >  Martijn
                          > >
                          > > Yes, you are measuring with RF square waves on these pins. As Robby says, worry when they are 0 or 5 volts.
                          > >
                          > > >
                          > > > On stage 6 I meusure the following voltages on u10 - FST3253
                          > > > Dont know why the voltages on pin 4 and 13 is so low?
                          > >
                          > > This is strange.
                          > > They are not used but would normally be about 2V5.
                          > > If they were shorted to ground then I'd expect them to affect other pins.
                          > > Maybe the FST3253 is faulty. But the pins that are used are correct.
                          > >
                          > > If no-one else has an answer I suggest you remember this and carry on to the next stage, you are almost there, maybe it will work.
                          > >
                          > > 73 Alan G4ZFQ
                          > >
                          >
                          > Very strange indeed.
                          > Losing more than 0.1 V on connections from U6 to U10 might be due to RF square wave effect.
                          > But pins 4, 5, 10, and 13 should be similar, they all are connected to the outputs for 1/4 of the RF period. One could speculate that since the pins with low voltage (4 and 13) both require S1 (pin 2) high, there could be something wrong with this switching signal.
                          > Maybe try resoldering pin 2 of U10?
                          > The only multimeter test that I can think of, would be the check of all pins of U10 for resistance to ground. In an unpowered circuit of course. This should reveal the possible partial shorts between tracks.
                          >
                          > If this reveals nothing, then follow Alan's advice.
                          >
                          > Regards,
                          > Ulo
                          >

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