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RE: [sl] King's Chamber of the Great Pyramid

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  • Barry Carroll
    virginia burt-- you are un- subscribed. sorry it took so long no excuse. barry
    Message 1 of 3 , Aug 31, 2001
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      virginia burt--
      you are un- subscribed.
      sorry it took so long
      no excuse.
      barry


      At 07:02 PM 8/21/01 -0400, you wrote:
      >Hi there I would like to unsubscribe - we tried once to no avail - please
      >reconfirm who the unsubscribe goes to. Thank you. Virginia
      >
      >-----Original Message-----
      >From:
      >sentto-1040416-1510-998329273-visions=interlynx.net@...
      >[mailto:sentto-1040416-1510-998329273-visions=interlynx.net@....
      >com]On Behalf Of Dan Washburn
      >Sent: August 20, 2001 4:31 PM
      >To: sacred landscape
      >Subject: [sl] King's Chamber of the Great Pyramid
      >
      >
      >In The Orion Mystery p44 Bauval and Gilbert give the
      >dimensions of The King's Chamber of the Great Pyramid as
      >5.23 meters wide by 10.46 meters long by 5.81 meters high.
      >Hence the floor of the chamber is a double square made up of
      >two squares 5.23 meters to the side.
      >
      >If the height of the chamber were 5.23, we would have a
      >double cube, but its not, its 5.81 meters. Why the
      >difference? Is there some way of deriving the height so
      >that it makes geometric sense?
      >
      >I set myself this problem the other day, figuring that
      >someone conversant with sacred geometry ought to be able to
      >figure it out.
      >
      >It took me about half an hour, so here is my idea:
      >
      >The height is one half the diagonal of the double square
      >rectangle. In my calculation it is 5.84, or 3 centimeters
      >difference from 5.81. This is a little more than one half a
      >percent of the whole (5.81), close enough for the difference
      >to be an error in measurement.
      >
      >Phi, the golden section, is .5 + (sqrt 5)/2. One half the
      >diagonal of the double square rectangle is the (sqrt 5)/2
      >part of the formula.
      >
      >The use of a double square rectangle in the pyramid points
      >to a knowledge of the golden section ratio, since the
      >doublesquare rectangle is used in the geometric construction
      >of phi. To find that the height of the King's Chamber is
      >one half the diagonal of the rectangle is near conclusive
      >evidence, since it is the diagonal of the doublesquare that
      >is the key to the geometric construction of phi.
      >
      >
      >By the way, Stecchini (Secrets of the Great Pyramid p 322)
      >says the pyramid and the King's Chamber is built in the
      >royal cubit of 524.1483 milimeters. 5.23 meters/524.1483
      >millimeters = 9.978 royal cubits. The chamber was meant to
      >be 10 royal cubits wide by 20 royal cubits long. Errors in
      >building, earthquake damage, or errors in measurement have
      >shifted things a bit off the true royal cubit dimensions for
      >the King's Chamber.
      >
      >Now if someone will tell me the religious meaning of the
      >King's Chamber and the coffer in the Chamber, I'd be much
      >obliged!
      >
      >Dan
      >
      >
      >
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      >
      >
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      >
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