I've made a slight improvement to the algorithm that factors integers by finding base for which the integer is a strong pseudoprime. To factor z, Initialize,kermit1941
Taking the remainder away from the quotient and letting the base for the remainder exponentiation be a*b, should speed things up a little... ?paulunderwooduk
I may have underestimated the time-saving.paulunderwooduk
who enjoy prime numbers. Some look for patterns,
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If you think you have a Goldbach proof, then please note that there are groups which deal specifically with such matters, perhaps try those first?
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- Number Theory
- Dec 27, 2000
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