veta function, again
yes I'm trying to work on Shane's function. I have:
1/(1-1/p^s)=1+ 1/p^s+ 1/p^2s+ 1/p^4s+ 1/p^6s+... (i.e. even exponents,
while the usual zeta function at this point is a sum over all
exponents. How do you solve the next stage, to get at the sum on the
left hand side of the veta function?)
where p is a prime divisor of Fq, such that the veta function is the
product over all p of this form.
I also have,
prod (p|Fq) (1-1/p)^(-1) +O(1/(log p)) as an attempt at getting to the
limit more rapidly, what do you think, David B?