Loading ...
Sorry, an error occurred while loading the content.

veta function, again

Expand Messages
  • Guy H Bearman
    hello yes I m trying to work on Shane s function. I have: 1/(1-1/p^s)=1+ 1/p^s+ 1/p^2s+ 1/p^4s+ 1/p^6s+... (i.e. even exponents, while the usual zeta function
    Message 1 of 1 , Oct 24, 2002
    • 0 Attachment
      hello

      yes I'm trying to work on Shane's function. I have:

      1/(1-1/p^s)=1+ 1/p^s+ 1/p^2s+ 1/p^4s+ 1/p^6s+... (i.e. even exponents,
      while the usual zeta function at this point is a sum over all
      exponents. How do you solve the next stage, to get at the sum on the
      left hand side of the veta function?)

      where p is a prime divisor of Fq, such that the veta function is the
      product over all p of this form.

      I also have,

      prod (p|Fq) (1-1/p)^(-1) +O(1/(log p)) as an attempt at getting to the
      limit more rapidly, what do you think, David B?

      Guy
    Your message has been successfully submitted and would be delivered to recipients shortly.