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Amazing cyclotomic factorization

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  • Renaud LIFCHITZ
    Hello all ! Let p = 3141592003181 Let N = Phi(6,p^20) = (p^60+1)/(p^20+1) (500 digits) Then N = 2161.43505714401.F.C with C unfactored and : F =
    Message 1 of 1 , Apr 2 12:33 PM
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      Hello all !

      Let p = 3141592003181
      Let N = Phi(6,p^20) = (p^60+1)/(p^20+1) (500 digits)

      Then N = 2161.43505714401.F.C with C unfactored and :

      F = 94885153006797735097780355737459994238807138067170/
      35705930587000916137586283228108163045885559189521 (100 digits)

      with F prime ! (proved by Titanix)

      This factor F=2.k.p+1, which has no specific form (take a look at F-1 and F+1),
      was found by my own special version of CarmiKiller in less than 10 minutes (no,
      that's not a joke !!!).

      This is a first result : others will follow...

      Regards,

      Renaud Lifchitz
      PARIS
      FRANCE



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