Well spotted. I had confused the numerator/denominator.

> I think that 2 actually

>_is_ an integer

and also a prime!

>After you've read Matthew 7 verse 5,that is.

Don't read the Bible. This verse states?

Jon Perry

perry@...
http://www.users.globalnet.co.uk/~perry/maths
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-----Original Message-----

From: Phil Carmody [mailto:

thefatphil@...]

Sent: 03 April 2002 00:03

To: primenumbers

Subject: Re: [PrimeNumbers] Lehmer Mack 2

--- Jon Perry <

perry@...> wrote:

> Consider phi(n^2)=k.(n-1)

>

> Obviously k contains some factor of n-1 in it's denominator.

>

> Therefore, as phi(n^2)=n.phi(n):

>

> phi(n)=(k/n).(n-1)

>

> And therefore k/n is never an integer.

Let n=2

Phi(2^2) = 2 = 2.(2-1)

=> k=2

=> k/n = 2

Now, as someone with "limited intelligence", I think that 2 actually

_is_ an integer, but am prepared to be proved wrong using your Most

Valued mathematical techniques. After you've read Matthew 7 verse 5,

that is.

Phil

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