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RE: [PrimeNumbers] Re: x+(y mod z) , kidding me?

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  • Paul Leyland
    ... That should be ... =4 except for 6. Paul
    Message 1 of 6 , Nov 28, 2001
      Oops, a minor typo in my previous mail:

      > Let N range over the integers 0, 1, 2, 3, ... and let f(N) have the
      > value N if the equation x^N+y^n = z^N has at least one solution in
      > integers x, y, z not all zero, and the value 2N othewise.
      >
      > Then 2 + f(N) generates 2, 3, and all even numbers >=4.

      That should be "... >=4 except for 6."


      Paul
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