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Re: Two factors of R(13860)

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  • d.broadhurst@open.ac.uk
    ... Sure thing, Boss! That folder is now totally Broadhurst free. Thanks for taking over! David
    Message 1 of 16 , Oct 2, 2001
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      Greg Childers commanded:
      > Delete the files you've uploaded
      > and I'll upload the updated versions.
      Sure thing, Boss! That folder is now
      totally Broadhurst free.
      Thanks for taking over!
      David
    • Satoshi TOMABECHI
      Thank you, Greg and David. My program shows that 15793939750*R(13860)/R(10)+1 is prime, however I have little confidence in this result:-) I hope that the
      Message 2 of 16 , Oct 2, 2001
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        Thank you, Greg and David.

        My program shows that 15793939750*R(13860)/R(10)+1 is prime,
        however I have little confidence in this result:-)
        I hope that the result is as same as David's.

        The coefficients of cubic equation t3X^3 + t2X^2 + t1X + t0 = 0 are

        t3 = 9499179946...9373462290 1400 digits
        t2 = 2983442091...4520303837 2765 digits
        t1 = -5786178299...9234821312 4165 digits
        t0 = -8297037200...6079883289 2764 digits

        The equation has three real roots r1,r2,r3.

        r1=-1.433940810...*10^{-1401}

        integral part of r2 246804372...4038770926 ( 1382 digits)
        fractional part of r2 0.9565089129....

        integral part of r3 -246804372...8946383526 ( 1382 digits)
        fractional part of r2 0.5941852755....

        Nearest integers of r1,r2 and r3 are not root of the equation.

        # It was not easy to compute roots of the cubic equation.

        Best regards.

        Satoshi Tomabechi
      • Satoshi TOMABECHI
        ... Yes, of course. Furthermore I coded modified KP with additional square tests by you. http://groups.yahoo.com/group/primeform/message/2142 But I have not
        Message 3 of 16 , Oct 2, 2001
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          David Broadhurst wrote:
          > Have you coded N+1?
          Yes, of course.
          Furthermore I coded modified KP
          with additional square tests by you.
          http://groups.yahoo.com/group/primeform/message/2142

          But I have not coded combined KP.
          http://groups.yahoo.com/group/primenumbers/message/1743

          > Have you coded 10/3*Max(F1,F2)+Min(F1,F2)>1 ?
          Sorry, I don't know such condition.
          Please tell me reference or pointer to reference.

          Satoshi Tomabechi
        • d.broadhurst@open.ac.uk
          ... By F1 and F2 I meant the fractions of N-1 and N+1. When F1 F2 this condition is what I used for Fib(25561), but it also works for F2 F1. Hence the Max and
          Message 4 of 16 , Oct 2, 2001
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            Satoshi TOMABECHI wrote:
            > > Have you coded 10/3*Max(F1,F2)+Min(F1,F2)>1 ?
            > Sorry, I don't know such condition.
            By F1 and F2 I meant the fractions of N-1 and N+1.
            When F1>F2 this condition is what I used for Fib(25561),
            but it also works for F2>F1. Hence the Max and Min.
            David
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