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Re: Two factors of R(13860)

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  • d.broadhurst@open.ac.uk
    ... Sorry about that. I had uploaded an old file. Have now remedied that, with your 2 gems at the top:-) ... Sorry, my file management skills are minimal. It s
    Message 1 of 16 , Oct 2, 2001
      Greg Childers wrote:
      > looks like David did the same at about the same time
      > but his is missing the 2 new factors
      Sorry about that. I had uploaded an old file.
      Have now remedied that, with your 2 gems at the top:-)
      > David...could you also update hd1k.zip with the 2 new factors and
      > Base10.zip with all 3 new factors?
      Sorry, my file management skills are minimal.
      It's already a minor miracle that I managed to
      get the previous version more or less OK.
      Please Greg, will you take over as Base10 DB manager?
      David
    • gchil0@pop.uky.edu
      ... OK, I ll delete mine. ... Sure. Delete the files you ve uploaded and I ll upload the updated versions. Greg
      Message 2 of 16 , Oct 2, 2001
        --- In primenumbers@y..., d.broadhurst@o... wrote:
        > Sorry about that. I had uploaded an old file.
        > Have now remedied that, with your 2 gems at the top:-)

        OK, I'll delete mine.

        > > David...could you also update hd1k.zip with the 2 new factors and
        > > Base10.zip with all 3 new factors?
        > Sorry, my file management skills are minimal.
        > It's already a minor miracle that I managed to
        > get the previous version more or less OK.
        > Please Greg, will you take over as Base10 DB manager?

        Sure. Delete the files you've uploaded and I'll upload the updated
        versions.

        Greg
      • d.broadhurst@open.ac.uk
        ... Sure thing, Boss! That folder is now totally Broadhurst free. Thanks for taking over! David
        Message 3 of 16 , Oct 2, 2001
          Greg Childers commanded:
          > Delete the files you've uploaded
          > and I'll upload the updated versions.
          Sure thing, Boss! That folder is now
          totally Broadhurst free.
          Thanks for taking over!
          David
        • Satoshi TOMABECHI
          Thank you, Greg and David. My program shows that 15793939750*R(13860)/R(10)+1 is prime, however I have little confidence in this result:-) I hope that the
          Message 4 of 16 , Oct 2, 2001
            Thank you, Greg and David.

            My program shows that 15793939750*R(13860)/R(10)+1 is prime,
            however I have little confidence in this result:-)
            I hope that the result is as same as David's.

            The coefficients of cubic equation t3X^3 + t2X^2 + t1X + t0 = 0 are

            t3 = 9499179946...9373462290 1400 digits
            t2 = 2983442091...4520303837 2765 digits
            t1 = -5786178299...9234821312 4165 digits
            t0 = -8297037200...6079883289 2764 digits

            The equation has three real roots r1,r2,r3.

            r1=-1.433940810...*10^{-1401}

            integral part of r2 246804372...4038770926 ( 1382 digits)
            fractional part of r2 0.9565089129....

            integral part of r3 -246804372...8946383526 ( 1382 digits)
            fractional part of r2 0.5941852755....

            Nearest integers of r1,r2 and r3 are not root of the equation.

            # It was not easy to compute roots of the cubic equation.

            Best regards.

            Satoshi Tomabechi
          • Satoshi TOMABECHI
            ... Yes, of course. Furthermore I coded modified KP with additional square tests by you. http://groups.yahoo.com/group/primeform/message/2142 But I have not
            Message 5 of 16 , Oct 2, 2001
              David Broadhurst wrote:
              > Have you coded N+1?
              Yes, of course.
              Furthermore I coded modified KP
              with additional square tests by you.
              http://groups.yahoo.com/group/primeform/message/2142

              But I have not coded combined KP.
              http://groups.yahoo.com/group/primenumbers/message/1743

              > Have you coded 10/3*Max(F1,F2)+Min(F1,F2)>1 ?
              Sorry, I don't know such condition.
              Please tell me reference or pointer to reference.

              Satoshi Tomabechi
            • d.broadhurst@open.ac.uk
              ... By F1 and F2 I meant the fractions of N-1 and N+1. When F1 F2 this condition is what I used for Fib(25561), but it also works for F2 F1. Hence the Max and
              Message 6 of 16 , Oct 2, 2001
                Satoshi TOMABECHI wrote:
                > > Have you coded 10/3*Max(F1,F2)+Min(F1,F2)>1 ?
                > Sorry, I don't know such condition.
                By F1 and F2 I meant the fractions of N-1 and N+1.
                When F1>F2 this condition is what I used for Fib(25561),
                but it also works for F2>F1. Hence the Max and Min.
                David
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