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Re: Two factors of R(13860)

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  • gchil0@pop.uky.edu
    Hi, ... I ve uploaded the factors to the files area. It can be downloaded at http://groups.yahoo.com/group/primenumbers/files/Factors/13860fac.zip Umm...looks
    Message 1 of 16 , Oct 2, 2001
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      Hi,

      > Where are factors of N-1? ( N=R(13860) )
      > Or please send me "help" file.
      > I would like to test primality.

      I've uploaded the factors to the files area. It can be downloaded at
      http://groups.yahoo.com/group/primenumbers/files/Factors/13860fac.zip

      Umm...looks like David did the same at about the same time :-) but his
      is missing the 2 new factors so I'll leave mine for now.

      David...could you also update hd1k.zip with the 2 new factors and
      Base10.zip with all 3 new factors?

      Thanks,
      Greg
    • d.broadhurst@open.ac.uk
      ... Sorry about that. I had uploaded an old file. Have now remedied that, with your 2 gems at the top:-) ... Sorry, my file management skills are minimal. It s
      Message 2 of 16 , Oct 2, 2001
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        Greg Childers wrote:
        > looks like David did the same at about the same time
        > but his is missing the 2 new factors
        Sorry about that. I had uploaded an old file.
        Have now remedied that, with your 2 gems at the top:-)
        > David...could you also update hd1k.zip with the 2 new factors and
        > Base10.zip with all 3 new factors?
        Sorry, my file management skills are minimal.
        It's already a minor miracle that I managed to
        get the previous version more or less OK.
        Please Greg, will you take over as Base10 DB manager?
        David
      • gchil0@pop.uky.edu
        ... OK, I ll delete mine. ... Sure. Delete the files you ve uploaded and I ll upload the updated versions. Greg
        Message 3 of 16 , Oct 2, 2001
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          --- In primenumbers@y..., d.broadhurst@o... wrote:
          > Sorry about that. I had uploaded an old file.
          > Have now remedied that, with your 2 gems at the top:-)

          OK, I'll delete mine.

          > > David...could you also update hd1k.zip with the 2 new factors and
          > > Base10.zip with all 3 new factors?
          > Sorry, my file management skills are minimal.
          > It's already a minor miracle that I managed to
          > get the previous version more or less OK.
          > Please Greg, will you take over as Base10 DB manager?

          Sure. Delete the files you've uploaded and I'll upload the updated
          versions.

          Greg
        • d.broadhurst@open.ac.uk
          ... Sure thing, Boss! That folder is now totally Broadhurst free. Thanks for taking over! David
          Message 4 of 16 , Oct 2, 2001
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            Greg Childers commanded:
            > Delete the files you've uploaded
            > and I'll upload the updated versions.
            Sure thing, Boss! That folder is now
            totally Broadhurst free.
            Thanks for taking over!
            David
          • Satoshi TOMABECHI
            Thank you, Greg and David. My program shows that 15793939750*R(13860)/R(10)+1 is prime, however I have little confidence in this result:-) I hope that the
            Message 5 of 16 , Oct 2, 2001
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              Thank you, Greg and David.

              My program shows that 15793939750*R(13860)/R(10)+1 is prime,
              however I have little confidence in this result:-)
              I hope that the result is as same as David's.

              The coefficients of cubic equation t3X^3 + t2X^2 + t1X + t0 = 0 are

              t3 = 9499179946...9373462290 1400 digits
              t2 = 2983442091...4520303837 2765 digits
              t1 = -5786178299...9234821312 4165 digits
              t0 = -8297037200...6079883289 2764 digits

              The equation has three real roots r1,r2,r3.

              r1=-1.433940810...*10^{-1401}

              integral part of r2 246804372...4038770926 ( 1382 digits)
              fractional part of r2 0.9565089129....

              integral part of r3 -246804372...8946383526 ( 1382 digits)
              fractional part of r2 0.5941852755....

              Nearest integers of r1,r2 and r3 are not root of the equation.

              # It was not easy to compute roots of the cubic equation.

              Best regards.

              Satoshi Tomabechi
            • Satoshi TOMABECHI
              ... Yes, of course. Furthermore I coded modified KP with additional square tests by you. http://groups.yahoo.com/group/primeform/message/2142 But I have not
              Message 6 of 16 , Oct 2, 2001
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                David Broadhurst wrote:
                > Have you coded N+1?
                Yes, of course.
                Furthermore I coded modified KP
                with additional square tests by you.
                http://groups.yahoo.com/group/primeform/message/2142

                But I have not coded combined KP.
                http://groups.yahoo.com/group/primenumbers/message/1743

                > Have you coded 10/3*Max(F1,F2)+Min(F1,F2)>1 ?
                Sorry, I don't know such condition.
                Please tell me reference or pointer to reference.

                Satoshi Tomabechi
              • d.broadhurst@open.ac.uk
                ... By F1 and F2 I meant the fractions of N-1 and N+1. When F1 F2 this condition is what I used for Fib(25561), but it also works for F2 F1. Hence the Max and
                Message 7 of 16 , Oct 2, 2001
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                  Satoshi TOMABECHI wrote:
                  > > Have you coded 10/3*Max(F1,F2)+Min(F1,F2)>1 ?
                  > Sorry, I don't know such condition.
                  By F1 and F2 I meant the fractions of N-1 and N+1.
                  When F1>F2 this condition is what I used for Fib(25561),
                  but it also works for F2>F1. Hence the Max and Min.
                  David
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