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Re: Two factors of R(13860)

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  • d.broadhurst@open.ac.uk
    ... I put it in http://groups.yahoo.com/group/primenumbers/files/Factors/HD13860.fac ... Just what we need, thanks. ... I bet! This simple, uncombined, KP is
    Message 1 of 16 , Oct 1, 2001
      Satoshi Tomabechi asked:
      > Where is "helper" file?
      I put it in
      http://groups.yahoo.com/group/primenumbers/files/Factors/HD13860.fac
      > My code may give a verification by another implementaion.
      Just what we need, thanks.
      > My code may also look "too" simple:-)
      I bet! This simple, uncombined, KP is easy, not so?
      Have you coded N+1?
      Have you coded 10/3*Max(F1,F2)+Min(F1,F2)>1 ?
      Best regards
      David
    • gchil0@pop.uky.edu
      Hi, ... I ve uploaded the factors to the files area. It can be downloaded at http://groups.yahoo.com/group/primenumbers/files/Factors/13860fac.zip Umm...looks
      Message 2 of 16 , Oct 2, 2001
        Hi,

        > Where are factors of N-1? ( N=R(13860) )
        > Or please send me "help" file.
        > I would like to test primality.

        I've uploaded the factors to the files area. It can be downloaded at
        http://groups.yahoo.com/group/primenumbers/files/Factors/13860fac.zip

        Umm...looks like David did the same at about the same time :-) but his
        is missing the 2 new factors so I'll leave mine for now.

        David...could you also update hd1k.zip with the 2 new factors and
        Base10.zip with all 3 new factors?

        Thanks,
        Greg
      • d.broadhurst@open.ac.uk
        ... Sorry about that. I had uploaded an old file. Have now remedied that, with your 2 gems at the top:-) ... Sorry, my file management skills are minimal. It s
        Message 3 of 16 , Oct 2, 2001
          Greg Childers wrote:
          > looks like David did the same at about the same time
          > but his is missing the 2 new factors
          Sorry about that. I had uploaded an old file.
          Have now remedied that, with your 2 gems at the top:-)
          > David...could you also update hd1k.zip with the 2 new factors and
          > Base10.zip with all 3 new factors?
          Sorry, my file management skills are minimal.
          It's already a minor miracle that I managed to
          get the previous version more or less OK.
          Please Greg, will you take over as Base10 DB manager?
          David
        • gchil0@pop.uky.edu
          ... OK, I ll delete mine. ... Sure. Delete the files you ve uploaded and I ll upload the updated versions. Greg
          Message 4 of 16 , Oct 2, 2001
            --- In primenumbers@y..., d.broadhurst@o... wrote:
            > Sorry about that. I had uploaded an old file.
            > Have now remedied that, with your 2 gems at the top:-)

            OK, I'll delete mine.

            > > David...could you also update hd1k.zip with the 2 new factors and
            > > Base10.zip with all 3 new factors?
            > Sorry, my file management skills are minimal.
            > It's already a minor miracle that I managed to
            > get the previous version more or less OK.
            > Please Greg, will you take over as Base10 DB manager?

            Sure. Delete the files you've uploaded and I'll upload the updated
            versions.

            Greg
          • d.broadhurst@open.ac.uk
            ... Sure thing, Boss! That folder is now totally Broadhurst free. Thanks for taking over! David
            Message 5 of 16 , Oct 2, 2001
              Greg Childers commanded:
              > Delete the files you've uploaded
              > and I'll upload the updated versions.
              Sure thing, Boss! That folder is now
              totally Broadhurst free.
              Thanks for taking over!
              David
            • Satoshi TOMABECHI
              Thank you, Greg and David. My program shows that 15793939750*R(13860)/R(10)+1 is prime, however I have little confidence in this result:-) I hope that the
              Message 6 of 16 , Oct 2, 2001
                Thank you, Greg and David.

                My program shows that 15793939750*R(13860)/R(10)+1 is prime,
                however I have little confidence in this result:-)
                I hope that the result is as same as David's.

                The coefficients of cubic equation t3X^3 + t2X^2 + t1X + t0 = 0 are

                t3 = 9499179946...9373462290 1400 digits
                t2 = 2983442091...4520303837 2765 digits
                t1 = -5786178299...9234821312 4165 digits
                t0 = -8297037200...6079883289 2764 digits

                The equation has three real roots r1,r2,r3.

                r1=-1.433940810...*10^{-1401}

                integral part of r2 246804372...4038770926 ( 1382 digits)
                fractional part of r2 0.9565089129....

                integral part of r3 -246804372...8946383526 ( 1382 digits)
                fractional part of r2 0.5941852755....

                Nearest integers of r1,r2 and r3 are not root of the equation.

                # It was not easy to compute roots of the cubic equation.

                Best regards.

                Satoshi Tomabechi
              • Satoshi TOMABECHI
                ... Yes, of course. Furthermore I coded modified KP with additional square tests by you. http://groups.yahoo.com/group/primeform/message/2142 But I have not
                Message 7 of 16 , Oct 2, 2001
                  David Broadhurst wrote:
                  > Have you coded N+1?
                  Yes, of course.
                  Furthermore I coded modified KP
                  with additional square tests by you.
                  http://groups.yahoo.com/group/primeform/message/2142

                  But I have not coded combined KP.
                  http://groups.yahoo.com/group/primenumbers/message/1743

                  > Have you coded 10/3*Max(F1,F2)+Min(F1,F2)>1 ?
                  Sorry, I don't know such condition.
                  Please tell me reference or pointer to reference.

                  Satoshi Tomabechi
                • d.broadhurst@open.ac.uk
                  ... By F1 and F2 I meant the fractions of N-1 and N+1. When F1 F2 this condition is what I used for Fib(25561), but it also works for F2 F1. Hence the Max and
                  Message 8 of 16 , Oct 2, 2001
                    Satoshi TOMABECHI wrote:
                    > > Have you coded 10/3*Max(F1,F2)+Min(F1,F2)>1 ?
                    > Sorry, I don't know such condition.
                    By F1 and F2 I meant the fractions of N-1 and N+1.
                    When F1>F2 this condition is what I used for Fib(25561),
                    but it also works for F2>F1. Hence the Max and Min.
                    David
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