Consider [5,2]

xX^2 = y^2 + y + x

if (y^2+x) is a square, then x is not a square.

if (y^2+y+x) is a square, then x is a square

xX^2 = (y+1)^2 + x - y + 1

As x =approx. y^(2/5), the RHS is not a square, therefore x is not a square.

Consider [5,4]

xX^2 = Y^2 + x - 1

As x =approx. y^(4/5), x is not a square.

Jon Perry

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