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Re: [PrimeNumbers] Re: Pell Equation

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  • Maximilian Hasler
    ... no : the 3rd equation is wrong. M. [Non-text portions of this message have been removed]
    Message 1 of 5 , Jun 23, 2013
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      On Sun, Jun 23, 2013 at 7:34 AM, djbroadhurst <d.broadhurst@...>wrote:

      > **
      > Kermit Rose <kermit@...> wrote:
      > > if
      > > a1^2 - d b1^2 = 1
      > > a2^2 - d b2^2 = 1
      > > then
      > > (a1^2 + d b1^2)^2 - (2 d a1 b1)^2 = 1
      > > (a1 a2 + d b1 b2)^2 - d (a1 b2 + b1 a2)^2 = 1
      >
      > Indeed.
      >

      no : the 3rd equation is wrong.

      M.


      [Non-text portions of this message have been removed]
    • Kermit Rose
      On 6/24/2013 12:07 PM, Maximilian Hasler ... (a1^2 + d b1^2)^2 - (2 d a1 b1)^2 = 1 should have been (a1^2 + d b1^2)^2 - d (2 a1 b1)^2 = 1 Kermit
      Message 2 of 5 , Jun 24, 2013
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        On 6/24/2013 12:07 PM,

        "Maximilian Hasler"

        wrote:
        > ________________________________________________________________________
        > 1a. Re: Pell Equation
        > Posted by: "Maximilian Hasler" maximilian.hasler@... maximilian_hasler
        > Date: Sun Jun 23, 2013 12:37 pm ((PDT))
        >
        >
        >> **
        >> Kermit Rose <kermit@...> wrote:
        >>> if
        >>> a1^2 - d b1^2 = 1
        >>> a2^2 - d b2^2 = 1
        >>> then
        >>> (a1^2 + d b1^2)^2 - (2 d a1 b1)^2 = 1
        >>> (a1 a2 + d b1 b2)^2 - d (a1 b2 + b1 a2)^2 = 1
        >>
        > no : the 3rd equation is wrong.
        >
        > M.
        >

        (a1^2 + d b1^2)^2 - (2 d a1 b1)^2 = 1

        should have been

        (a1^2 + d b1^2)^2 - d (2 a1 b1)^2 = 1


        Kermit
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