- --- In primenumbers@yahoogroups.com, Sebastian Martin Ruiz <s_m_ruiz@...> wrote:
>

Based on Warren's (corrected) simplification to your equation

>

> Prove:

>

> Theorem:

>

> Let c a positive even number >2

>

> If x=1 and y=1 is the only positive solution of the polynomial

>

> -3x^2+y^2-2xy-4cx+4cy+4=0

>

> then c +1 and c-1 are twin primes

>

> Sincerely

>

> Sebastián Martín Ruiz

>

> [Non-text portions of this message have been removed]

>

-3x^2 + y^2 -2xy - 4cx + 4cy + 4 = 0

namely

r^2 - x^2 - c^2 + 1 = 0

then I can prove something close, that if

(x,y) = (1,1) and ( (c^2)/2 - 1,3(c^2)/2 - 2c - 1)

are the only positive solutions to your equation, then c+1 and c-1 are twin primes.

Addendum:

If c is even and greater than 2, there are at least two unique solutions, as per above.

If c is odd and greater than 5, there are at least three unique solutions::

(x,y) = (1,1) and ((c^2 - 1)/4 - 1, 3(c^2 - 1)/4 - 2c + 1) and

((c^2 - 1)/8 - 2, 3(c^2 - 1)/8 - 2c + 2)

Mark - Sorry If (1,1) and (c^2/2-1, 3c^2/2-2c-1) are the only integer solutions then c+1 y c-1 are twin primes

Enviado desde Yahoo! Mail con Android

[Non-text portions of this message have been removed] - In

http://tech.groups.yahoo.com/group/primenumbers/message/24217

SMR wrote:

"

Sorry. I promise not to send anything if I'm not sure that's interesting.

"

when I said:> It's not nice to obfuscate simple expressions

This was on 17.4.2012.

> to make serious people loose their time.

When I search "obfuscated Ruiz" in my mailbox,

the next earlier instance is from 16.3.2011,

and even earlier ones on 22.9.2010 and 31.8.2010.

Probably there are more using other terms....

Given that the case seems hopeless,

I finally didn't work out and send off the answer I was tempted to make.

M.

On Sun, May 26, 2013 at 6:38 PM, Sebastian Martin Ruiz <s_m_ruiz@...>wrote:

> **

> Sorry If (1,1) and (c^2/2-1, 3c^2/2-2c-1) are the only integer solutions

>

of the equation

A*B = (c-1)(c+1) ,

(where the above (x,y) correspond to A=1 resp. A=c-1)

> then c+1 y c-1 are twin primes

>

Obviously, indeed.

As usual, sufficiently obfuscated to have several people loose some hours

on that....

Maximilian

[Non-text portions of this message have been removed]