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RE: Is the twin prime constant irrational?

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  • Kermit Rose
    I expected the twin prime constant to be irrational because I expected that any constant that requires EVERY prime in order to calculate it, would necessarily
    Message 1 of 7 , Feb 13, 2013
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      I expected the twin prime constant to be irrational
      because I expected that any constant
      that requires EVERY prime in order to calculate it,

      would necessarily be irrational.

      Kermit Rose
    • bobgillson
      Surely the rationality of irrationality depends on the truth of otherwise of the twin prime conjecture. ... [Non-text portions of this message have been
      Message 2 of 7 , Feb 13, 2013
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        Surely the rationality of irrationality depends on the truth of otherwise of the twin prime conjecture.

        On 13 Feb 2013, at 17:15, Kermit Rose <kermit@...> wrote:

        > I expected the twin prime constant to be irrational
        > because I expected that any constant
        > that requires EVERY prime in order to calculate it,
        >
        > would necessarily be irrational.
        >
        > Kermit Rose
        >
        >


        [Non-text portions of this message have been removed]
      • Jack Brennen
        What is the product over all of the primes p of: (p^2+1)/(p^2-1) ? That s a constant that requires EVERY prime in order to calculate it. It turns out to be
        Message 3 of 7 , Feb 13, 2013
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          What is the product over all of the primes p of:

          (p^2+1)/(p^2-1) ?

          That's a constant that requires EVERY prime in order
          to calculate it.

          It turns out to be 5/2. Which is not irrational.



          On 2/13/2013 9:15 AM, Kermit Rose wrote:
          > I expected the twin prime constant to be irrational
          > because I expected that any constant
          > that requires EVERY prime in order to calculate it,
          >
          > would necessarily be irrational.
          >
          > Kermit Rose
          >
          >
          >
          >
          > ------------------------------------
          >
          > Unsubscribe by an email to: primenumbers-unsubscribe@yahoogroups.com
          > The Prime Pages : http://primes.utm.edu/
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        • djbroadhurst
          ... Nice point, Jack. print(zeta(2)^2/zeta(4)); 2.5000000000000000000000000000000000000 David
          Message 4 of 7 , Feb 13, 2013
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            --- In primenumbers@yahoogroups.com, Jack Brennen wrote:
            >
            > What is the product over all of the primes p of:
            >
            > (p^2+1)/(p^2-1) ?
            >
            > That's a constant that requires EVERY prime in order
            > to calculate it.
            >
            > It turns out to be 5/2. Which is not irrational.

            Nice point, Jack.

            print(zeta(2)^2/zeta(4));
            2.5000000000000000000000000000000000000

            David
          • Kermit Rose
            Re: Is the twin prime constant irrational? Twin prime constant = (3/2)(1/2)(5/4)(3/4)(7/6)(5/6)(11/10)(9/10)...(p/(p-1))((p-2)/(p-1))... I expected that it
            Message 5 of 7 , Feb 15, 2013
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              Re: Is the twin prime constant irrational?



              Twin prime constant
              = (3/2)(1/2)(5/4)(3/4)(7/6)(5/6)(11/10)(9/10)...(p/(p-1))((p-2)/(p-1))...


              I expected that it would have been easily determined whether or not
              the twin prime constant was rational or irrational.

              It would not be possible for the twin prime constant to be rational
              because the infinite numerator is odd, and the infinite denominator is
              divisible by
              2 infinitely many times.

              Kermit
            • Jack Brennen
              How about this infinite product here? (99/10)*(111/110)*(1111/1110)*(11111/11110)*... The partial products are: 9.9 9.99 9.999 9.9999 and so on... The product
              Message 6 of 7 , Feb 15, 2013
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                How about this infinite product here?

                (99/10)*(111/110)*(1111/1110)*(11111/11110)*...

                The partial products are:
                9.9
                9.99
                9.999
                9.9999
                and so on...

                The product quite obviously converges to an even number (10), but all of
                the numerators are odd and all of the denominators are even. Even and
                odd really have no meaning when it comes to infinity and limits. As
                this example shows, a series of partial products, all of which have
                odd numerator and even denominator, can converge to not only a rational
                number, but an even integer.


                On 2/15/2013 8:53 AM, Kermit Rose wrote:
                > Re: Is the twin prime constant irrational?
                >
                >
                >
                > Twin prime constant
                > = (3/2)(1/2)(5/4)(3/4)(7/6)(5/6)(11/10)(9/10)...(p/(p-1))((p-2)/(p-1))...
                >
                >
                > I expected that it would have been easily determined whether or not
                > the twin prime constant was rational or irrational.
                >
                > It would not be possible for the twin prime constant to be rational
                > because the infinite numerator is odd, and the infinite denominator is
                > divisible by
                > 2 infinitely many times.
                >
                > Kermit
                >
                >
                >
                >
                >
                >
                > ------------------------------------
                >
                > Unsubscribe by an email to: primenumbers-unsubscribe@yahoogroups.com
                > The Prime Pages : http://primes.utm.edu/
                >
                > Yahoo! Groups Links
                >
                >
                >
                >
                >
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