Hello Sebastian,

I think it is trivial.

m=(p+q)/2

z1=m-k and z2=m+k are prime.

m-k+m+k=2m=p+q. So m-k =p and m+k=q , your primes to calculate m.

Norman

________________________________

Von: Sebastian Martin Ruiz <

s_m_ruiz@...>

An: "

primenumbers@yahoogroups.com" <

primenumbers@yahoogroups.com>

Gesendet: 20:19 Samstag, 16.Juni 2012

Betreff: [PrimeNumbers] more equivalence theorem

Hello all:

Also we have:

Theorem:

Let p and q consecutive prime numbers >=5

Let m=(p+q)/2

m+6 is prime if and only if m-6 is prime.

Sincerely

Sebastian Martin Ruiz

then for k=2 , 3 , and 6

m+k is prime if and only if m-k is prime.

I think is possible to found more k....

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