We say that primes must have only 2 divisors. In other hand, if number has

2 divisors, it's prime.

2 is also prime and the first element and only even element of prime set.

What must we name the numbers which have 3 or 5 or 7 or... divisors? It can

be interesting to think about these.

As we know, 6, 28, ... are perfect numbers.

But let's think:

any a natural number has a[1], a[2], ... , a[n] divisors. Clearly, we see

a[n]=n;

if a[1]+a[2]+...+a[n-1]=a then a-->perfect number.

if a[1]*a[2]*a[3]*...*a[n-1]=a then a--> ?

after some tests, we can see if a[1]*a[2]*...*a[n-1]=a then absolutely,

n=3... a has 3 divisors.

*Question: is there any a natural number that:

1) it has more than 3 divisors;*

*2) a=a[1]*a[2]*a[n-1]....?*

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