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Re: prime_n^(1/n) - prime_(n+1)^(1/(n+1))

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  • djbroadhurst
    ... but meant to write (1 - a(k)) = (log(k)/k)*(1 + O(log(log(k))/log(k)))
    Message 1 of 4 , Feb 2 10:05 AM
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      --- In primenumbers@yahoogroups.com,
      "djbroadhurst" <d.broadhurst@...> wrote:

      > a(k) = 2 - prime(k+1)^(1/(k+1))
      > (1 - a(k))*log(k)/k = 1 + O(log(log(k))/log(k))

      but meant to write

      (1 - a(k)) = (log(k)/k)*(1 + O(log(log(k))/log(k)))
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