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Re: [PrimeNumbers] Re: Primes with the representation of the year in them

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  • Phil Carmody
    ... Yeah, I m clearly confused. This happens occasionally. Phil
    Message 1 of 17 , Nov 26, 2011
      --- On Fri, 11/25/11, djbroadhurst <d.broadhurst@...> wrote:
      > Phil Carmody <thefatphil@...> wrote:
      > > I see no reason why larger p wouldn't permit us to cover
      > > everything divisible by 2011 with other primes
      > The concept of a covering set is familiar in the context of
      > (n^q + c)/d, with (n, c, d) held fixed, but not (to me at least)
      > in the present context, with  (q = p^p, c = 2, d = 2011) held fixed
      > and only the base, n, allowed to vary.
      > >  I would expect it to be quite easy to arrive at a 0 answer.
      > I am unable to do so except in the trivial cases p = 3 and
      > p = 67.
      > On the contrary, I conjecture that for every prime p that does not
      > divide znorder(Mod(-2,2011)) = 3*67 there is an infinitude
      > of primes
      > of the form (n^(p^p)+2)/2011, with fixed p, even though we
      > presently know of no probable prime in any case with p > 5.

      Yeah, I'm clearly confused. This happens occasionally.

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