Loading ...
Sorry, an error occurred while loading the content.

Riemann Zeta Result

Expand Messages
  • Sebastian Martin Ruiz
    Hello:   I have obtained this interesting limit whit Riemann Zeta function:   Limit {x- 0}
    Message 1 of 2 , Oct 21, 2011
    • 0 Attachment
      Hello:
       
      I have obtained
      this interesting limit whit Riemann Zeta function:
       
      Limit {x->0} (Zeta[2+(x!)^x]-Zeta[3])Log[x]/(x(Zeta[3]-Zeta[2+x^x]))=EulerGamma=0.57721...
       
      I have
      deduced this from: n>=3 positive integer:
       
      Lim
      {x->0} (Zeta[n-1+x^x]-Zeta[n])/(x Log[x])= Sum {k>=1} Log[k]/k^n
       
      And:
       
      Lim
      {x->0} (Zeta[2+(x!)^x]-Zeta[3])/(x^2) = EulerGamma*Sum {k>=1} Log[k]/k^3
       
      I have
      obtained all results using WolframAlpha and MATHEMATICA.
       
      Sincerely:
       
      Sebastián
      Martín Ruiz

      [Non-text portions of this message have been removed]
    Your message has been successfully submitted and would be delivered to recipients shortly.