Hi , all ,

Not even draft yet , let alone published :

http://upforthecount.com/math/nnp.html
still needs a lot of work .

But , I have updated the top of the main table :

http://upforthecount.com/math/nnp2.txt
with complete factorizations now extending through

np ( 90 ) .

When is np ( n ) prime ?

So far , only for 1 , 2 and 3 .

When n mod 6 = 4 , np ( n ) has at least 3 algebraic

factors , 3 and n^2 + n + 1 ( twice ) .

But what about the residue ( primitive part ? ) ?

When is this prime ?

n t n^n + (n+1)^(n+1)

4 4 3 * 7 * 7 * 23

16 6 3 * 7 * 7 * 13 * 13 * 34041259347101651

Any others ?

Cheers ,

Walter