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Re: [PrimeNumbers] to verify it

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  • Maximilian Hasler
    no : nobody can send you such a number, because 10^99 10^198 and therefore n 10^395 Maximilian
    Message 1 of 2 , Mar 26, 2011
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      no : nobody can send you such a number,
      because 10^99 < p-q < sqrt (p)
      implies that p > 10^198 and therefore n > 10^395

      Maximilian




      On Sat, Mar 26, 2011 at 8:04 AM, Éric Judor <ric.judor@...> wrote:
      > can someone send to me a real numbre  satisfy  p - q < sqrt(p)
      >
      >  maximum  digits for n = 300 digit
      >
      >   minimum digits for p-q = 100
      >
      > note n= p*q
      >             p>q
      >            p-q <  sqrt(p)
      >
      >
      >
      >
      > [Non-text portions of this message have been removed]
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