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Re: Prime chains x-->Ax+B [puzzle 2]

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  • djbroadhurst
    ... Suppose that we want to start with a square and get a square. Then we must solve the Diophantine equation y^2 = a*x^2 + b For any pair (a,b), Dario will
    Message 1 of 143 , Jan 7, 2011
      --- In primenumbers@yahoogroups.com,
      Kevin Acres <research@...> wrote:

      > x=a*x+b either is a square or has a square as a major factor.

      Suppose that we want to start with a square and get a square.
      Then we must solve the Diophantine equation
      y^2 = a*x^2 + b

      For any pair (a,b), Dario will tell us all the solutions:
      http://www.alpertron.com.ar/QUAD.HTM

      David
    • djbroadhurst
      ... Suppose that we want to start with a square and get a square. Then we must solve the Diophantine equation y^2 = a*x^2 + b For any pair (a,b), Dario will
      Message 143 of 143 , Dec 7, 1936
        --- In primenumbers@yahoogroups.com,
        Kevin Acres <research@...> wrote:

        > x=a*x+b either is a square or has a square as a major factor.

        Suppose that we want to start with a square and get a square.
        Then we must solve the Diophantine equation
        y^2 = a*x^2 + b

        For any pair (a,b), Dario will tell us all the solutions:
        http://www.alpertron.com.ar/QUAD.HTM

        David
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