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AW: [PrimeNumbers] Re: 2011 !

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  • Norman Luhn
    ... sum (157..211) =2011
    Message 1 of 1 , Dec 31, 2010
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      >Can you solve, by hand:

      >"Two thousand "eleven" is the sum of 11 consecutive primes. Can you find them?"

      sum (157..211) =2011
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