Loading ...
Sorry, an error occurred while loading the content.

Re: Prime chains x-->Ax+B [puzzle 11]

Expand Messages
  • djbroadhurst
    ... Starting with 3, 11 ... , Phil found a third 11/12: {A=[507876501124257];q=3; for(k=1,#A,a=A[k];b=11-q*a;p=q;if(a%11==1, for(n=1,12,print1(isprime(p)
    Message 1 of 143 , Dec 5, 2010
    • 0 Attachment
      --- In primenumbers@yahoogroups.com,
      "djbroadhurst" <d.broadhurst@...> wrote:

      > Congrats to Phil for scoring 11/12, twice

      Starting with 3, 11 ... , Phil found a third 11/12:

      {A=[507876501124257];q=3;
      for(k=1,#A,a=A[k];b=11-q*a;p=q;if(a%11==1,
      for(n=1,12,print1(isprime(p)" ");p=a*p+b));print());}

      1 1 1 1 1 1 1 1 1 1 1 0

      David
    • djbroadhurst
      ... Suppose that we want to start with a square and get a square. Then we must solve the Diophantine equation y^2 = a*x^2 + b For any pair (a,b), Dario will
      Message 143 of 143 , Jan 7, 2011
      • 0 Attachment
        --- In primenumbers@yahoogroups.com,
        Kevin Acres <research@...> wrote:

        > x=a*x+b either is a square or has a square as a major factor.

        Suppose that we want to start with a square and get a square.
        Then we must solve the Diophantine equation
        y^2 = a*x^2 + b

        For any pair (a,b), Dario will tell us all the solutions:
        http://www.alpertron.com.ar/QUAD.HTM

        David
      Your message has been successfully submitted and would be delivered to recipients shortly.