- View Source--- In primenumbers@yahoogroups.com,

Phil Carmody <thefatphil@...> wrote:

> > but then it did indeed start to get tough.

...

> Corroborated: (and here, as 2 are for free, 7=9)

> 9 519815699116440

...

> 9 1188368874866394

Congrats to Phil for scoring 11/12, twice:

{A=[519815699116440,1188368874866394];q=2;

for(k=1,#A,a=A[k];b=11-q*a;p=q;if(a%11==1,

for(n=1,12,print1(isprime(p)" ");p=a*p+b));print());}

1 1 1 1 1 1 1 1 1 1 1 0

1 1 1 1 1 1 1 1 1 1 1 0

David - View Source--- In primenumbers@yahoogroups.com,

Kevin Acres <research@...> wrote:

> x=a*x+b either is a square or has a square as a major factor.

Suppose that we want to start with a square and get a square.

Then we must solve the Diophantine equation

y^2 = a*x^2 + b

For any pair (a,b), Dario will tell us all the solutions:

http://www.alpertron.com.ar/QUAD.HTM

David