The Squaring of Twin Primes
- Jack Brennen wrote;
"Don't you mean that A and B are the larger members of those twin prime
Yes, Jack that is what I meant. I mixed them up when I wrote the post. Thank you for correcting me and also for why the rightmost digit must always be 1.
Tom Hadley wrote:
For any X of the form X = 6*k+/-1, note that (5*X^2-1)/4 will be of the
form 6*m+1, so it can never be the smaller member of a twin prime pair.
Here's how one would go about determining this:"
Thank you Tom for your neat explanation. It seems so obvious now, but the fact that A and B will always be large twins with rightmost digits equal to 1 had me stumped.
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