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Additional condition

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  • Ситников Сергей
    David, while I ll deal with your comment, look at the additional condition Additional condition (m) - Prime number m_p P_n^2
    Message 1 of 2 , Jul 8, 2010
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      David, while I'll deal with your comment, look at the additional condition
      Additional condition
      (m) - Prime number m_p
      P_n^2<m_p<P_(n+1)^2
      P_n - Primes
      n – prime number
      m*P_(n+1)/P(n+1)-1=m_1
      The interval (m_p, m_1)
      One prime 90% of cases, all decisions
      0 or 2 primes of 10% of cases, all decisions
    • djbroadhurst
      ... {forprime(m=2,300, p=nextprime(ceil(sqrt(m))); m1=floor(m*p/(p-1));v=[]; forprime(q=m+1,m1,v=concat(v,q)); if(#v 2,print([m,v])));} [101, [103, 107, 109]]
      Message 2 of 2 , Jul 8, 2010
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        --- In primenumbers@yahoogroups.com,
        <chitatel2000@...> wrote:

        > (m) - Prime number m_p
        > P_n^2<m_p<P_(n+1)^2
        > P_n - Primes
        > n â€" prime number
        > m*P_(n+1)/P(n+1)-1=m_1
        > The interval (m_p, m_1)
        > One prime 90% of cases, all decisions
        > 0 or 2 primes of 10% of cases, all decisions

        {forprime(m=2,300,
        p=nextprime(ceil(sqrt(m)));
        m1=floor(m*p/(p-1));v=[];
        forprime(q=m+1,m1,v=concat(v,q));
        if(#v>2,print([m,v])));}

        [101, [103, 107, 109]]
        [103, [107, 109, 113]]
        [191, [193, 197, 199]]
        [223, [227, 229, 233]]
        [227, [229, 233, 239, 241]]
        [229, [233, 239, 241]]
        [257, [263, 269, 271]]
        [263, [269, 271, 277]]
        [269, [271, 277, 281, 283]]
        [271, [277, 281, 283]]
        [277, [281, 283, 293]]

        David
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