Re: a*x^n+b*y^n puzzle
- I wonder if any mileage can be got from the identity (provided x<>y):-
- --- In email@example.com,
"Robdine" <robdine@...> wrote:
> any rational prime that can be represented by the sumThere is only rational prime of the form a^2 + b^2 that yields
> of 2 squares (a^2+b^2) will define 4 gaussian primes
precisely 4 distinct Gaussian primes, namely 2 = 1^2 + 1^2.
If a^2 + b^2 is an odd rational prime, we have
8 [sic] asociates of the Gaussian prime z = a + I*b,
since we may mulitply it and its conjugate z = a - I*b
by the 4 units I, -I, -1, 1, obtaining 8 distinct
Gaussian integers that are prime.