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RE: [PrimeNumbers] Curious equivalence

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  • Chris Caldwell
    ...   Well, that is true for n 1, but of course n!/(n_1)! = n, and n#/(n-1)# = 1 if n is composite and n if n is prime. Note however that by the convention
    Message 1 of 2 , Jul 19, 2009
      > n is prime if and only if   n!/(n-1)!=n#/(n-1)#
       
      Well, that is true for n>1, but of course n!/(n_1)! = n, and n#/(n-1)# = 1 if n is
      composite and n if n is prime.

      Note however that by the convention empty products are 1 (0! = 1, 1# = 0# = 1) we
      have n!/(n-1)!=n#/(n-1)# for n=1.

      CC
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