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Re: trying to expose pseudo's

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  • David Broadhurst
    ... 2^52 - 2 = 1 mod 13
    Message 1 of 2 , May 3, 2009
      --- In primenumbers@yahoogroups.com,
      Bill Bouris <leavemsg1@...> wrote:

      > sorry if I'm not using the maths totally correctly
      > 2^(Q-1)-2 mod 'q' == -1, 0

      2^52 - 2 = 1 mod 13
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