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Re: [PrimeNumbers] Gaps distribution: Conjecture

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  • Andrey Kulsha
    Hello! ... Sorry, exp( -g / (log x - log(log x)) ) is right. Therefore 436 is right in Milton s example instead of 433. However, log log x is too small, so
    Message 1 of 8 , Jul 26, 2001
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      Hello!

      Andrey Kulsha wrote:

      > General result: the probability of a given gap g around the number x being
      > greater than G is about
      >
      > exp( -g / (log x + log(log x)) ).

      Sorry, exp( -g / (log x - log(log x)) ) is right.

      Therefore 436 is right in Milton's example instead of 433.

      However, log log x is too small, so

      exp( -g / log x)

      is good enough.

      Best wishes,

      Andrey
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