## is this absurd?

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• Take a decimal r belonging to R. Es. 13.77, Ok now raise the square and to do so using a linear combination: (13.77) ^ 2 = 13 ^ 2 + 13 * 0.77 + 13.77 * 0.77 /
Message 1 of 2 , Nov 29, 2007
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Take a decimal r belonging to R.
Es. 13.77,

Ok now raise the square and to do so using a linear combination:

(13.77) ^ 2 = 13 ^ 2 + 13 * 0.77 + 13.77 * 0.77 / / this and how to
write only 13.77 * 13.77.

But now explain the algorithm.

So is the square of one decimal place in linear combination:

(X.y) ^ 2 = x ^ 2 + x * 0.y + xy * 0.y

But for an algorithm change one small thing ...

(X.y) ^ 2 = x ^ 2 + x * y + xy * 0.y
The algorithm begins with x> 1

For the second step does not do 13 * 0.77 but 13 * 77

Es. X = 13 y = 77, r = 13.77

169 + 1001 + 9.8329 ... Ok, I write 9.8329 as a whole without dot 98329

And do 169 + 1001 + 98329 = 99499 ...

Another example:

r = 5.2

(5.2) ^ 2 = 25 + 5 * 2 + 5.2 * 0.2 = 35 + 1.04 as I write 35 + 104 = 139

Another example still

r = 64.202

(64.202) ^ 2 = 4096 + 64 * 202 + 12.968804 = 4096 + 12928 + 12.968804 ...

Ok do 4096 + 1001 + 12968804 = 13010771 ...

Another example

r = 1.002

(1.002) ^ 2 = 1 + 1 * 2 + 1.002 * 0.002 =

1 + 2 + 0.002004 = 3 + 2004 = 2007

r = 1.1

1 + 1 * 1 + 1.1 * 0.1 = 1 + 1 + 11 = 13

-REFLECTION

If the algorithm work:
But the cardinality of R > N, and then if all r return with the
algorithm a prime
We would have an infinite of primes, that are much more then these
naturals, and nature of this is absurd.

reguards Alby7e7
• ... Without commenting on the stuff about prime numbers, I d point out that the cardinality of the rational numbers is the same as the cardinality of the
Message 2 of 2 , Nov 29, 2007
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alby7e7 wrote:
> -REFLECTION
>
> If the algorithm work:
> But the cardinality of R > N, and then if all r return with the
> algorithm a prime
> We would have an infinite of primes, that are much more then these
> naturals, and nature of this is absurd.
>

Without commenting on the stuff about prime numbers, I'd point out
that the cardinality of the rational numbers is the same as the
cardinality of the natural numbers... And your algorithm only
works for a subset of the rational numbers -- those with a terminating
decimal expansion. (A number with an infinite decimal expansion
could not map to a finite natural number using your algorithm.)

Plug in r = Pi to your algorithm and tell me what the output is. :)
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