Re: [PrimeNumbers] Powers of Two Primes
> The other conjecture is that alternate power of two numbersProof:
> are divisible by 3.
Sum(i=0..N, 10^something(i)*2^i) mod 3 =
Sum(i=0..N, 2^i) mod 3 =
2^(N+1)-1 mod 3 =
0 for odd N, 1 for even N.
[Name] Peter Kosinar [Quote] 2B | ~2B = exp(i*PI) [ICQ] 134813278