RE probability of a number being square free
>What is the probability of a number being square free... it seems thatThe density of numbers being nth-powerfree is 1/zeta(n), where zeta is the Riemann Zeta
>the more square free numbers than the non-square free numbers for big
>numbers. Would be interested to know more details about the same.
>Any reference for the same?
Function. So, for squarefree numbers, we have your probability is 1/zeta(2) = 6 / pi^2 ~
Regards. Jose Brox