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2/3 * 7/5 * ...

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  • Werner D. Sand
    Let be product = 2/3 * 7/5 * 11/13 * 19/17 * ... * p(n)/p(n+1) * p(n+3)/p(n+2) * ... I thought, product would be = 1, but obviously it is not. After 2*10^7
    Message 1 of 1 , Mar 18, 2007
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      Let be product = 2/3 * 7/5 * 11/13 * 19/17 * ...
      * p(n)/p(n+1) * p(n+3)/p(n+2) * ...

      I thought, product would be = 1, but obviously it is not. After 2*10^7
      steps (factors, ratios) I got product = 0.9049044468… Who can compute
      further?
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