## Re: proving the Riemann hypothesis

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• Hello Shi Huang, what do you mean by unpredictable ? Simple example: If you build S = abs(M + or – N), where M,N are coprimes and M*N includes the whole
Message 1 of 40 , Feb 3, 2007
Hello Shi Huang,

what do you mean by "unpredictable"? Simple example: If you build
S = abs(M + or  N), where M,N are coprimes and M*N includes the whole
sequence of prime factors from 2 to p(n), and if S < (p(n+1))², then
you can "predict" that S is prime. I don't say this is a practical
method for finding prime numbers.

Werner
• For example 2 adjacent gaps cannot be equal if they aren t multiple of 6. For example the gap between 2 pairs of twins is at least 4. For example each prime
Message 40 of 40 , Feb 7, 2007
For example 2 adjacent gaps cannot be equal if they aren't multiple of
6. For example the gap between 2 pairs of twins is at least 4. For
example each prime number has the form 2n+/-1, 3n+/-1, 4n+/-1, 6n+/-1.
Each pair of twins has the form 12n+-1, there are approximate formulas
for the nth prime and the number of primes < x and so on. You cannot
call all this random ore unpredictable. Of course the prime numbers are
distributed as regularly as possible, that's a tautology. In
mathematics everything is as regular as possible. Is pi random? Build
P=2,357111317192329, and you have the same case as pi. Consider the
primes to be an irrational number, and there are no problems. If you
mean there is no formula f(n) which produces primes for each n, then
you are right. In this sense primes are random. (I am not quite sure 
there is a formula p=[k^n^3] (H.W.Mills) which is said to produce only
prime numbers). If you define "formula" as an algorithm, as a
calculation instruction such as the sieve of Eratosthenes, then the
primes are not random but simply what they are. Perhaps the compound
numbers are random? Or are they only non-transparently complicated?

Werner
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